वर्गमूल सर्पिल में पहले समकोण त्रिभुज की दोनों लंब भुजाएँ (1) इकाई हों तो कर्ण कौन-सा होगा?

In a square root spiral, if both perpendicular sides of the first right triangle are (1) unit, what will be the hypotenuse?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\sqrt{2}\)

Step 1

Concept

The hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). This follows from Pythagoras theorem.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{2}\). The hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). This follows from Pythagoras theorem.

Step 3

Exam Tip

कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। यह पाइथागोरस प्रमेय से मिलता है।

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वर्गमूल सर्पिल में पहले समकोण त्रिभुज की दोनों लंब भुजाएँ (1) इकाई हों तो कर्ण कौन-सा होगा? / In a square root spiral, if both perpendicular sides of the first right triangle are (1) unit, what will be the hypotenuse?

Correct Answer: B. \(\sqrt{2}\). Explanation: कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। यह पाइथागोरस प्रमेय से मिलता है। / The hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). This follows from Pythagoras theorem.

Which concept should I revise for this Mathematics MCQ?

The hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). This follows from Pythagoras theorem.

What exam hint can help solve this Mathematics question?

कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। यह पाइथागोरस प्रमेय से मिलता है।