वर्गमूल सर्पिल में \(\sqrt{8}\) के बाद (1) इकाई लंब जोड़ने पर अगला कर्ण कौन-सा होगा?
In a square root spiral, after \(\sqrt{8}\), which hypotenuse is obtained by adding a (1) unit perpendicular?
Explanation opens after your attempt
C. \(\sqrt{9}\)
Concept
The new hypotenuse is \(\sqrt{8+1}=\sqrt{9}\). The next step always gives the square root of the next integer.
Why this answer is correct
The correct answer is C. \(\sqrt{9}\). The new hypotenuse is \(\sqrt{8+1}=\sqrt{9}\). The next step always gives the square root of the next integer.
Exam Tip
नया कर्ण \(\sqrt{8+1}=\sqrt{9}\) होगा। अगला चरण हमेशा अगले पूर्णांक का वर्गमूल देता है।
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