वर्गमूल सर्पिल में \(\sqrt{8}\) के बाद (1) इकाई लंब जोड़ने पर अगला कर्ण कौन-सा होगा?

In a square root spiral, after \(\sqrt{8}\), which hypotenuse is obtained by adding a (1) unit perpendicular?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. \(\sqrt{9}\)

Step 1

Concept

The new hypotenuse is \(\sqrt{8+1}=\sqrt{9}\). The next step always gives the square root of the next integer.

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{9}\). The new hypotenuse is \(\sqrt{8+1}=\sqrt{9}\). The next step always gives the square root of the next integer.

Step 3

Exam Tip

नया कर्ण \(\sqrt{8+1}=\sqrt{9}\) होगा। अगला चरण हमेशा अगले पूर्णांक का वर्गमूल देता है।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{8}\) के बाद (1) इकाई लंब जोड़ने पर अगला कर्ण कौन-सा होगा? / In a square root spiral, after \(\sqrt{8}\), which hypotenuse is obtained by adding a (1) unit perpendicular?

Correct Answer: C. \(\sqrt{9}\). Explanation: नया कर्ण \(\sqrt{8+1}=\sqrt{9}\) होगा। अगला चरण हमेशा अगले पूर्णांक का वर्गमूल देता है। / The new hypotenuse is \(\sqrt{8+1}=\sqrt{9}\). The next step always gives the square root of the next integer.

Which concept should I revise for this Mathematics MCQ?

The new hypotenuse is \(\sqrt{8+1}=\sqrt{9}\). The next step always gives the square root of the next integer.

What exam hint can help solve this Mathematics question?

नया कर्ण \(\sqrt{8+1}=\sqrt{9}\) होगा। अगला चरण हमेशा अगले पूर्णांक का वर्गमूल देता है।