यदि ((c-6)x-8+\(c^2-36\)x-5+31) की डिग्री (0) है, तो (c) का मान क्या है?
If the degree of ((c-6)x-8+\(c^2-36\)x-5+31) is (0), what is the value of (c)?
Explanation opens after your attempt
A. (c=6)
Concept
For degree (0), both \(x^8\) and \(x^5\) terms must vanish. At (c=6), both coefficients become (0).
Why this answer is correct
The correct answer is A. (c=6). For degree (0), both \(x^8\) and \(x^5\) terms must vanish. At (c=6), both coefficients become (0).
Exam Tip
डिग्री (0) के लिए \(x^8\) और \(x^5\) दोनों पद हटने चाहिए। (c=6) पर दोनों गुणांक (0) हो जाते हैं।
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