यदि \(\sqrt{90}\) सर्पिल में मिला है, तो इसका सरलतम रूप क्या है?

If \(\sqrt{90}\) is obtained in the spiral, what is its simplest form?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(3\sqrt{10}\)

Step 1

Concept

\(\sqrt{90}=\sqrt{9\times10}=3\sqrt{10}\). Take the perfect square (9) outside.

Step 2

Why this answer is correct

The correct answer is A. \(3\sqrt{10}\). \(\sqrt{90}=\sqrt{9\times10}=3\sqrt{10}\). Take the perfect square (9) outside.

Step 3

Exam Tip

\(\sqrt{90}=\sqrt{9\times10}=3\sqrt{10}\)। पूर्ण वर्ग (9) को बाहर निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\sqrt{90}\) सर्पिल में मिला है, तो इसका सरलतम रूप क्या है? / If \(\sqrt{90}\) is obtained in the spiral, what is its simplest form?

Correct Answer: A. \(3\sqrt{10}\). Explanation: \(\sqrt{90}=\sqrt{9\times10}=3\sqrt{10}\)। पूर्ण वर्ग (9) को बाहर निकालें। / \(\sqrt{90}=\sqrt{9\times10}=3\sqrt{10}\). Take the perfect square (9) outside.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{90}=\sqrt{9\times10}=3\sqrt{10}\). Take the perfect square (9) outside.

What exam hint can help solve this Mathematics question?

\(\sqrt{90}=\sqrt{9\times10}=3\sqrt{10}\)। पूर्ण वर्ग (9) को बाहर निकालें।