If s = 2, what is the degree of (s − 2)x⁶ + (s + 5)x³ + 9?
Answer and explanation
Correct answer: 3
Substitute s = 2. The coefficient of x⁶ becomes s − 2 = 0, so the sixth-degree term disappears. The coefficient of x³ becomes s + 5 = 7, which is non-zero. The expression reduces to 7x³ + 9, whose highest exponent is 3. Therefore its degree is 3; the vanished x⁶ term and the constant 9 do not change this result.
Frequently asked questions
What is the correct answer to this question?
3
Why is this the correct answer?
Substitute s = 2. The coefficient of x⁶ becomes s − 2 = 0, so the sixth-degree term disappears. The coefficient of x³ becomes s + 5 = 7, which is non-zero. The expression reduces to 7x³ + 9, whose highest exponent is 3. Therefore its degree is 3; the vanished x⁶ term and the constant 9 do not change this result.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Degree of a Polynomial.
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