यदि (p(x)=x-6\(x^2-7\)-x-8+7x-6+31), तो (p(x)) की डिग्री क्या है?
If (p(x)=x-6\(x^2-7\)-x-8+7x-6+31), what is the degree of (p(x))?
Explanation opens after your attempt
D. (0)
Concept
(x-6\(x^2-7\)=x-8-7x-6). All variable terms cancel and (31) remains, whose degree is (0).
Why this answer is correct
The correct answer is D. (0). (x-6\(x^2-7\)=x-8-7x-6). All variable terms cancel and (31) remains, whose degree is (0).
Exam Tip
(x-6\(x^2-7\)=x-8-7x-6) है। सभी चर पद कट जाते हैं और (31) बचता है जिसकी डिग्री (0) है।
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