यदि \(a=\sqrt{2}\) तो \(a+\frac{1}{a}\) किस प्रकार की संख्या है?
If \(a=\sqrt{2}\) then \(a+\frac{1}{a}\) is what type of number?
Explanation opens after your attempt
Correct Answer
C. अपरिमेयIrrational
Concept
\(\sqrt{2}+\frac{\sqrt{2}}{2}\) remains irrational. Use properties of irrationals.
Why this answer is correct
The correct answer is C. अपरिमेय / Irrational. \(\sqrt{2}+\frac{\sqrt{2}}{2}\) remains irrational. Use properties of irrationals.
Exam Tip
\(\sqrt{2}+\frac{\sqrt{2}}{2}\) अपरिमेय रहता है। अपरिमेय के गुण पहचानें।
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