वर्गमूल सर्पिल में \(\sqrt{11}\) से नया कर्ण बनाने पर कौन-सा मिलेगा?

If a new hypotenuse is made from \(\sqrt{11}\) in a square root spiral, which one is obtained?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \(\sqrt{12}\)

Step 1

Concept

Taking a (1) unit perpendicular with \(\sqrt{11}\) gives \(\sqrt{12}\). This is the step rule of the spiral.

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{12}\). Taking a (1) unit perpendicular with \(\sqrt{11}\) gives \(\sqrt{12}\). This is the step rule of the spiral.

Step 3

Exam Tip

\(\sqrt{11}\) के साथ (1) इकाई लंब लेने पर \(\sqrt{12}\) बनता है। यह सर्पिल का क्रमिक नियम है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{11}\) से नया कर्ण बनाने पर कौन-सा मिलेगा? / If a new hypotenuse is made from \(\sqrt{11}\) in a square root spiral, which one is obtained?

Correct Answer: C. \(\sqrt{12}\). Explanation: \(\sqrt{11}\) के साथ (1) इकाई लंब लेने पर \(\sqrt{12}\) बनता है। यह सर्पिल का क्रमिक नियम है। / Taking a (1) unit perpendicular with \(\sqrt{11}\) gives \(\sqrt{12}\). This is the step rule of the spiral.

Which concept should I revise for this Mathematics MCQ?

Taking a (1) unit perpendicular with \(\sqrt{11}\) gives \(\sqrt{12}\). This is the step rule of the spiral.

What exam hint can help solve this Mathematics question?

\(\sqrt{11}\) के साथ (1) इकाई लंब लेने पर \(\sqrt{12}\) बनता है। यह सर्पिल का क्रमिक नियम है।