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If (a^2=2b^2) and (a=2r), what combined conclusion about (a) and (b) follows from (b^2=2r^2)?

Answer and explanation

Correct answer: Both are even

From a=2r, a is a multiple of 2, so a is even. From b^2=2r^2, b^2 is even. If the square of an integer is even, then the integer itself must be even; hence b is even. Therefore, both a and b are even. They need not both be zero, since non-zero even integers are also possible. Exam tip: In the irrationality proof, this result contradicts the assumption that a and b are coprime.

Related tags

Number SystemsIrrationality ProofSquare Root Of 2Even And OddContradiction ProofProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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