For which value will ((w^2-100)x^{14}+(w-10)x^8+3x^2-6) have degree (2)?किस मान पर ((w^2-100)x^{14}+(w-10)x^8+3x^2-6) की डिग्री (2) होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (w=10)(w=10)
For degree (2), both (x^{14}) and (x^8) terms must vanish. At (w=10), both coefficients become (0).डिग्री (2) के लिए (x^{14}) और (x^8) दोनों पद हटने चाहिए। (w=10) पर दोनों गुणांक (0) हो जाते हैं।
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