डिग्री (2) के लिए \(x^{14}\) और \(x^8\) दोनों पद हटने चाहिए। (w=10) पर दोनों गुणांक (0) हो जाते हैं। / For degree (2), both \(x^{14}\) and \(x^8\) terms must vanish. At (w=10), both coefficients become (0).
Mathematics Answer, Explanation and Revision Hints
किस मान पर (\(w^2-100\)x^{14}+(w-10)x-8+3x-2-6) की डिग्री (2) होगी? / For which value will (\(w^2-100\)x^{14}+(w-10)x-8+3x-2-6) have degree (2)?
Correct Answer: A. (w=10). Explanation: डिग्री (2) के लिए \(x^{14}\) और \(x^8\) दोनों पद हटने चाहिए। (w=10) पर दोनों गुणांक (0) हो जाते हैं। / For degree (2), both \(x^{14}\) and \(x^8\) terms must vanish. At (w=10), both coefficients become (0).
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