किस मान पर (\(u^2-36\)x^{10}+(u+6)x-5+7) की डिग्री (0) होगी?
For which value will (\(u^2-36\)x^{10}+(u+6)x-5+7) have degree (0)?
Explanation opens after your attempt
B. (u=-6)
Concept
For degree (0), both \(x^{10}\) and \(x^5\) terms must vanish. At (u=-6), both coefficients are (0).
Why this answer is correct
The correct answer is B. (u=-6). For degree (0), both \(x^{10}\) and \(x^5\) terms must vanish. At (u=-6), both coefficients are (0).
Exam Tip
डिग्री (0) के लिए \(x^{10}\) और \(x^5\) दोनों पद हटने चाहिए। (u=-6) पर दोनों गुणांक (0) हैं।
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