किस मान पर (\(s^2-1\)x-8+(s+1)x-6+5) की डिग्री (0) होगी?

For which value will (\(s^2-1\)x-8+(s+1)x-6+5) have degree (0)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (s=-1)

Explanation

Simple Explanation

डिग्री (0) के लिए \(x^8\) और \(x^6\) दोनों पद हटने चाहिए। (s=-1) पर दोनों गुणांक (0) हो जाते हैं। / For degree (0), both \(x^8\) and \(x^6\) terms must vanish. At (s=-1), both coefficients become (0).

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FAQs

Mathematics Answer, Explanation and Revision Hints

किस मान पर (\(s^2-1\)x-8+(s+1)x-6+5) की डिग्री (0) होगी? / For which value will (\(s^2-1\)x-8+(s+1)x-6+5) have degree (0)?

Correct Answer: B. (s=-1). Explanation: डिग्री (0) के लिए \(x^8\) और \(x^6\) दोनों पद हटने चाहिए। (s=-1) पर दोनों गुणांक (0) हो जाते हैं। / For degree (0), both \(x^8\) and \(x^6\) terms must vanish. At (s=-1), both coefficients become (0).