किस मान पर (\(s^2-1\)x-8+(s+1)x-6+5) की डिग्री (0) होगी?
For which value will (\(s^2-1\)x-8+(s+1)x-6+5) have degree (0)?
Explanation opens after your attempt
B. (s=-1)
Concept
For degree (0), both \(x^8\) and \(x^6\) terms must vanish. At (s=-1), both coefficients become (0).
Why this answer is correct
The correct answer is B. (s=-1). For degree (0), both \(x^8\) and \(x^6\) terms must vanish. At (s=-1), both coefficients become (0).
Exam Tip
डिग्री (0) के लिए \(x^8\) और \(x^6\) दोनों पद हटने चाहिए। (s=-1) पर दोनों गुणांक (0) हो जाते हैं।
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