Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 91-100 of 600 questions.
If the sum of the first (n) natural numbers is (325), what will (n) be?
C. (25)
\(S_{25}=\frac{25\times26}{2}=325\) इसलिए (n=25)। दिए गए योग को सूत्र से मिलाकर देखें। / \(S_{25}=\frac{25\times26}{2}=325\), so (n=25). Match the given sum with the formula.
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What is the value of \(1+2+3+\cdots+27\)?
C. (378)
\(S_{27}=\frac{27\times28}{2}=378\) है। (28) को पहले (14) में बदलें। / \(S_{27}=\frac{27\times28}{2}=378\). Change (28) to (14) first.
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Choose the correct option for the sum of the first (33) natural numbers.
B. (561)
\(S_{33}=\frac{33\times34}{2}=561\) है। (34) का आधा (17) लेकर गुणा करें। / \(S_{33}=\frac{33\times34}{2}=561\). Take half of (34) as (17) and multiply.
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C. (171)
कुल सितारे \(S_{18}=\frac{18\times19}{2}=171\) हैं। पंक्ति संख्या बढ़ने पर प्राकृतिक संख्याओं का योग बनता है। / Total stars are \(S_{18}=\frac{18\times19}{2}=171\). Increasing row counts form the sum of natural numbers.
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If \(S_n=465\), what is the value of (n) for the first (n) natural numbers?
C. (30)
\(S_{30}=\frac{30\times31}{2}=465\) इसलिए (n=30)। विकल्पों को सूत्र में रखकर जल्दी उत्तर मिल सकता है। / \(S_{30}=\frac{30\times31}{2}=465\), so (n=30). Substituting options in the formula can give a quick answer.
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What is the sum of the first (100) natural numbers?
B. (5050)
\(S_{100}=\frac{100\times101}{2}=5050\) है। (100) तक के योग का मान याद रखना भी उपयोगी है। / \(S_{100}=\frac{100\times101}{2}=5050\). Remembering the sum up to (100) is also useful.
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What is the sum of the first (37) natural numbers?
B. (703)
\(S_{37}=\frac{37\times38}{2}=703\) है। विषम (n) में अगले सम गुणक को आधा करें। / \(S_{37}=\frac{37\times38}{2}=703\). For odd (n), halve the next even factor.
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Choose the correct sum of \(1+2+3+\cdots+42\).
A. (903)
\(S_{42}=\frac{42\times43}{2}=903\) होता है। सम (n) को (2) से भाग देकर गणना आसान करें। / \(S_{42}=\frac{42\times43}{2}=903\). Divide the even (n) by (2) to make calculation easier.
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If the sum of the first (n) natural numbers is (861), what is the value of (n)?
C. (41)
\(S_{41}=\frac{41\times42}{2}=861\) इसलिए (n=41)। ऐसे प्रश्नों में विकल्पों को सूत्र में रखकर जांचें। / \(S_{41}=\frac{41\times42}{2}=861\), so (n=41). In such questions, check the options in the formula.
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In a school, badge numbers from (1) to (38) are given. What will be the sum of all badge numbers?
B. (741)
सभी बैज नंबरों का योग \(S_{38}=\frac{38\times39}{2}=741\) है। लगातार (1) से शुरू होने पर अंतिम संख्या को (n) मानें। / The sum of all badge numbers is \(S_{38}=\frac{38\times39}{2}=741\). When counting starts from (1), take the last number as (n).
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