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\( \sqrt{16} \) किस प्रकार की वास्तविक संख्या है?
What type of real number is \( \sqrt{16} \)?
#real numbers
#class 9
#square root
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A अपरिमेय संख्या / Irrational number
B परिमेय संख्या / Rational number
C न वास्तविक संख्या / Not a real number
D अपरिभाषित संख्या / Undefined number
Explanation opens after your attempt
Correct Answer
B. परिमेय संख्या / Rational number
Step 1
Concept
\( \sqrt{16}=4 \), and (4) is rational. The square root of a perfect square is rational.
Step 2
Why this answer is correct
The correct answer is B. परिमेय संख्या / Rational number. \( \sqrt{16}=4 \), and (4) is rational. The square root of a perfect square is rational.
Step 3
Exam Tip
\( \sqrt{16}=4 \) है और (4) परिमेय संख्या है। पूर्ण वर्ग का वर्गमूल परिमेय होता है।
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\( \sqrt{7} \) के बारे में सही विकल्प चुनिए।
Choose the correct option about \( \sqrt{7} \).
#real numbers
#class 9
#irrational square root
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A यह पूर्णांक है / It is an integer
B यह परिमेय संख्या है / It is a rational number
C यह वास्तविक नहीं है / It is not real
D यह अपरिमेय वास्तविक संख्या है / It is an irrational real number
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Correct Answer
D. यह अपरिमेय वास्तविक संख्या है / It is an irrational real number
Step 1
Concept
(7) is not a perfect square, so \( \sqrt{7} \) is irrational. Still, it is a real number.
Step 2
Why this answer is correct
The correct answer is D. यह अपरिमेय वास्तविक संख्या है / It is an irrational real number. (7) is not a perfect square, so \( \sqrt{7} \) is irrational. Still, it is a real number.
Step 3
Exam Tip
(7) पूर्ण वर्ग नहीं है इसलिए \( \sqrt{7} \) अपरिमेय है। फिर भी यह वास्तविक संख्या है।
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\( \sqrt{25} \) का वास्तविक मान क्या है?
What is the real value of \( \sqrt{25} \)?
#real numbers
#class 9
#perfect square
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A (5)
B (10)
C \( \frac{25}{2} \)
D \( \sqrt{50} \)
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Step 1
Concept
\( \sqrt{25}=5 \) because \(5^2=25\). Identify square roots of perfect squares quickly.
Step 2
Why this answer is correct
The correct answer is A. (5). \( \sqrt{25}=5 \) because \(5^2=25\). Identify square roots of perfect squares quickly.
Step 3
Exam Tip
\( \sqrt{25}=5 \) क्योंकि \(5^2=25\)। पूर्ण वर्गों के वर्गमूल जल्दी पहचानें।
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\( \sqrt{2} \) का अनुमानित स्थान किसके बीच है?
The approximate position of \( \sqrt{2} \) is between which numbers?
#real numbers
#class 9
#square root location
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A (0) और (1) / (0) and (1)
B (1) और (2) / (1) and (2)
C (2) और (3) / (2) and (3)
D (3) और (4) / (3) and (4)
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Correct Answer
B. (1) और (2) / (1) and (2)
Step 1
Concept
Since \(1^2<2<2^2\), \( \sqrt{2} \) lies between (1) and (2). Compare squares to locate square roots.
Step 2
Why this answer is correct
The correct answer is B. (1) और (2) / (1) and (2). Since \(1^2<2<2^2\), \( \sqrt{2} \) lies between (1) and (2). Compare squares to locate square roots.
Step 3
Exam Tip
\(1^2<2<2^2\) इसलिए \( \sqrt{2} \) (1) और (2) के बीच है। वर्गों की तुलना से वर्गमूल का स्थान मिलता है।
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\( \sqrt{9}+\sqrt{4} \) का मान क्या है?
What is the value of \( \sqrt{9}+\sqrt{4} \)?
#real numbers
#class 9
#square roots
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A (5)
B \( \sqrt{13} \)
C (7)
D (1)
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Step 1
Concept
\( \sqrt{9}=3 \) and \( \sqrt{4}=2 \), so the sum is (5). First find square roots of perfect squares.
Step 2
Why this answer is correct
The correct answer is A. (5). \( \sqrt{9}=3 \) and \( \sqrt{4}=2 \), so the sum is (5). First find square roots of perfect squares.
Step 3
Exam Tip
\( \sqrt{9}=3 \) और \( \sqrt{4}=2 \) इसलिए योग (5) है। पहले पूर्ण वर्गों के वर्गमूल निकालें।
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\( \sqrt{49} \) कौन सी संख्या है?
What type of number is \( \sqrt{49} \)?
#real numbers
#class 9
#perfect square
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A अपरिमेय वास्तविक संख्या / Irrational real number
B परिमेय वास्तविक संख्या / Rational real number
C अपरिभाषित संख्या / Undefined number
D नकारात्मक संख्या / Negative number
Explanation opens after your attempt
Correct Answer
B. परिमेय वास्तविक संख्या / Rational real number
Step 1
Concept
\( \sqrt{49}=7 \), and (7) is a rational real number. The square root of a perfect square can be an integer.
Step 2
Why this answer is correct
The correct answer is B. परिमेय वास्तविक संख्या / Rational real number. \( \sqrt{49}=7 \), and (7) is a rational real number. The square root of a perfect square can be an integer.
Step 3
Exam Tip
\( \sqrt{49}=7 \) है और (7) परिमेय वास्तविक संख्या है। पूर्ण वर्ग का वर्गमूल पूर्णांक हो सकता है।
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\( -\sqrt{4} \) का मान क्या है?
What is the value of \( -\sqrt{4} \)?
#real numbers
#class 9
#negative square root
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A (2)
B ( -2 )
C (4)
D ( -4 )
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Step 1
Concept
\( \sqrt{4}=2 \), so \( -\sqrt{4}=-2 \). Apply the outside negative sign after finding the square root.
Step 2
Why this answer is correct
The correct answer is B. ( -2 ). \( \sqrt{4}=2 \), so \( -\sqrt{4}=-2 \). Apply the outside negative sign after finding the square root.
Step 3
Exam Tip
\( \sqrt{4}=2 \) इसलिए \( -\sqrt{4}=-2 \)। वर्गमूल निकालने के बाद बाहर का ऋण चिह्न लगाएँ।
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\( \sqrt{121} \) का मान क्या है?
What is the value of \( \sqrt{121} \)?
#real numbers
#class 9
#square root
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A (10)
B (11)
C (12)
D (121)
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Step 1
Concept
Since \(11^2=121\), \( \sqrt{121}=11 \). Remembering perfect squares is useful.
Step 2
Why this answer is correct
The correct answer is B. (11). Since \(11^2=121\), \( \sqrt{121}=11 \). Remembering perfect squares is useful.
Step 3
Exam Tip
\(11^2=121\) इसलिए \( \sqrt{121}=11 \)। पूर्ण वर्गों की सूची याद रखना उपयोगी है।
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\( \sqrt{5} \) और \( \sqrt{6} \) में कौन बड़ी है?
Which is greater between \( \sqrt{5} \) and \( \sqrt{6} \)?
#real numbers
#class 9
#square root comparison
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A \( \sqrt{5} \)
B \( \sqrt{6} \)
C दोनों बराबर / Both are equal
D दोनों वास्तविक नहीं / Both are not real
Explanation opens after your attempt
Correct Answer
B. \( \sqrt{6} \)
Step 1
Concept
For positive numbers, the square root of the greater number is also greater. Since (6>5), \( \sqrt{6}>\sqrt{5} \).
Step 2
Why this answer is correct
The correct answer is B. \( \sqrt{6} \). For positive numbers, the square root of the greater number is also greater. Since (6>5), \( \sqrt{6}>\sqrt{5} \).
Step 3
Exam Tip
धनात्मक संख्याओं में बड़ी संख्या का वर्गमूल भी बड़ा होता है। (6>5) इसलिए \( \sqrt{6}>\sqrt{5} \)।
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वास्तविक संख्या रेखा पर \( \sqrt{0} \) कहाँ स्थित है?
Where is \( \sqrt{0} \) located on the real number line?
#real numbers
#class 9
#zero square root
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A (0) पर / At (0)
B (1) पर / At (1)
C ( -1 ) पर / At ( -1 )
D (2) पर / At (2)
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Correct Answer
A. (0) पर / At (0)
Step 1
Concept
\( \sqrt{0}=0 \). Therefore it is located at the origin on the number line.
Step 2
Why this answer is correct
The correct answer is A. (0) पर / At (0). \( \sqrt{0}=0 \). Therefore it is located at the origin on the number line.
Step 3
Exam Tip
\( \sqrt{0}=0 \) होता है। इसलिए यह संख्या रेखा पर मूल बिंदु पर स्थित है।
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