Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 431-440 of 600 questions.
What is the simplified form of \(\sqrt{98}\)?
A. \(7\sqrt{2}\)
\(98=49\times2\) इसलिए \(\sqrt{98}=7\sqrt{2}\)। पूर्ण वर्ग अलग करें। / \(98=49\times2\), so \(\sqrt{98}=7\sqrt{2}\). Extract the perfect square.
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B. \(\frac{1}{2}\)
समाप्त दशमलव \(0.5=\frac{1}{2}\) होता है। दशमलव को भिन्न में बदलें। / The terminating decimal \(0.5=\frac{1}{2}\). Convert decimals to fractions.
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If \(a=\sqrt{3}\) then what is \(2a+\sqrt{3}\)?
C. \(3\sqrt{3}\)
\(2\sqrt{3}+\sqrt{3}=3\sqrt{3}\)। समान पद जोड़ें। / \(2\sqrt{3}+\sqrt{3}=3\sqrt{3}\). Add like terms.
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Which statement is not correct?
C. हर अपरिमेय संख्या परिमेय हैEvery irrational number is rational
अपरिमेय और परिमेय अलग वर्ग हैं। यह कथन गलत है। / Irrational and rational numbers are different classes. Hence this statement is false.
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What is the simplified form of \(\sqrt{24}+\sqrt{54}\)?
A. \(5\sqrt{6}\)
\(\sqrt{24}=2\sqrt{6}\) और \(\sqrt{54}=3\sqrt{6}\)। योग \(5\sqrt{6}\) है। / \(\sqrt{24}=2\sqrt{6}\) and \(\sqrt{54}=3\sqrt{6}\). Sum is \(5\sqrt{6}\).
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Which number is not an integer?
D. \(\frac{9}{2}\)
\(\frac{9}{2}=4.5\) पूर्णांक नहीं है। अन्य सभी पूर्णांक हैं। / \(\frac{9}{2}=4.5\) is not an integer. The others are integers.
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What is the value of \(\sqrt{3}\times\sqrt{12}\)?
A. 6
\(\sqrt{36}=6\) प्राप्त होता है। मूलों का गुणन करें। / You get \(\sqrt{36}=6\). Multiply the radicals.
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If a rational number has an infinite decimal expansion then it will be?
B. आवर्तीRepeating
परिमेय संख्या का अनंत दशमलव आवर्ती होता है। यह मानक परिणाम है। / An infinite decimal expansion of a rational number is repeating. This is a standard result.
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What is the simplified form of \(\sqrt{72}\)?
A. \(6\sqrt{2}\)
\(72=36\times2\) इसलिए \(\sqrt{72}=6\sqrt{2}\)। पूर्ण वर्ग निकालें। / \(72=36\times2\), so \(\sqrt{72}=6\sqrt{2}\). Extract the perfect square.
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What is the value of \(\sqrt{125}-\sqrt{5}\)?
B. \(4\sqrt{5}\)
\(\sqrt{125}=5\sqrt{5}\) इसलिए उत्तर \(4\sqrt{5}\) है। सरल रूप आवश्यक है। / \(\sqrt{125}=5\sqrt{5}\), so the answer is \(4\sqrt{5}\). Simplify first.
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