Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 371-380 of 600 questions.
In the line \(y=\frac{7}{3}x-5\), how much should (x) increase to increase (y) by (21)?
C. (9)
परिवर्तन \(\frac{7}{3}\Delta x=21\) होगा। इससे \(\Delta x=9\) मिलता है। / The change is \(\frac{7}{3}\Delta x=21\). This gives \(\Delta x=9\).
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If (p=-5) and (q=-4) in (y=px+q), which statement is correct?
B. रेखा घटती है और (y)-अवरोध ऋणात्मक हैThe line decreases and (y)-intercept is negative
(p=-5) ऋणात्मक ढाल देता है और (q=-4) ऋणात्मक (y)-अवरोध देता है। इसलिए रेखा घटती है। / (p=-5) gives a negative slope and (q=-4) gives a negative (y)-intercept. So the line decreases.
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If (3x+ay=24) has (y)-intercept (6), what is (a)?
C. (4)
(x=0) रखने पर (ay=24) और \(y=\frac{24}{a}\) मिलता है। \(\frac{24}{a}=6\) से (a=4) है। / Putting (x=0) gives (ay=24) and \(y=\frac{24}{a}\). From \(\frac{24}{a}=6\), (a=4).
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If (bx+6y=30) has slope (-2), what is (b)?
C. (12)
(6y=-bx+30) से ढाल \(-\frac{b}{6}\) है। \(-\frac{b}{6}=-2\) से (b=12) मिलता है। / From (6y=-bx+30), the slope is \(-\frac{b}{6}\). From \(-\frac{b}{6}=-2\), (b=12).
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The line (y=(n-3)x+(2n-5)) has (y)-intercept (7). What is its slope?
C. (2)
(2n-5=7) से (n=6) मिलता है। ढाल (n-3=3) नहीं, (3) है इसलिए विकल्प (D) सही है। / From (2n-5=7), (n=6). The slope is (n-3=3), so option (D) is correct.
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The line (y=(t-6)x+(t+2)) has slope (4). What is its (y)-intercept?
C. (12)
(t-6=4) से (t=10) मिलता है। (y)-अवरोध (t+2=12) है। / From (t-6=4), (t=10). The (y)-intercept is (t+2=12).
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Which line cuts the (y)-axis at ( (0,-8) ) and increases (y) by (18) when (x) increases by (3)?
A. (y=6x-8)
ढाल \(\frac{18}{3}=6\) है और (y)-अवरोध (-8) है। इसलिए रेखा (y=6x-8) है। / The slope is \(\frac{18}{3}=6\) and the (y)-intercept is (-8). So the line is (y=6x-8).
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Which line cuts the (y)-axis at ( (0,12) ) and decreases (y) by (20) when (x) increases by (4)?
B. (y=-5x+12)
ढाल \(-\frac{20}{4}=-5\) है और (y)-अवरोध (12) है। इसलिए (y=-5x+12) सही है। / The slope is \(-\frac{20}{4}=-5\) and the (y)-intercept is (12). So (y=-5x+12) is correct.
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If (y=(a+2)x+(a-9)) passes through the origin, what will be its slope?
C. (11)
मूल बिंदु से गुजरने के लिए (a-9=0) होगा। इसलिए (a=9) और ढाल (a+2=11) है। / To pass through the origin, (a-9=0). Thus (a=9) and the slope is (a+2=11).
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If (y=(2u-1)x+(u+3)) has (y)-intercept (11), what is the slope?
A. (15)
(u+3=11) से (u=8) मिलता है। ढाल (2u-1=15) है। / From (u+3=11), (u=8). The slope is (2u-1=15).
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