Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 391-400 of 600 questions.
The line (y=mx-3) passes through ( (8,1) ). What is (m)?
A. \( \frac{1}{2} \)
बिंदु रखने पर (1=8m-3) मिलता है। इससे (8m=4) और \(m=\frac{1}{2}\) है। / Substituting the point gives (1=8m-3). Thus (8m=4) and \(m=\frac{1}{2}\).
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If (y=(3a-2)x+(a+1)) has (y)-intercept (6), what is the slope?
C. (13)
(a+1=6) से (a=5) मिलता है। ढाल (3a-2=13) है। / From (a+1=6), (a=5). The slope is (3a-2=13).
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If (y=(b-7)x+(2b+1)) has slope (2), what is the (y)-intercept?
C. (19)
(b-7=2) से (b=9) मिलता है। (y)-अवरोध (2b+1=19) है। / From (b-7=2), (b=9). The (y)-intercept is (2b+1=19).
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What are the slope and (y)-intercept of (2x-3y+9=0)?
A. ढाल \(\frac{2}{3}\), (y)-अवरोध (3)Slope \(\frac{2}{3}\), (y)-intercept (3)
(-3y=-2x-9) से \(y=\frac{2}{3}x+3\) मिलता है। इसलिए ढाल \(\frac{2}{3}\) और (y)-अवरोध (3) है। / From (-3y=-2x-9), \(y=\frac{2}{3}x+3\). So the slope is \(\frac{2}{3}\) and the (y)-intercept is (3).
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If (y=(t+1)x-4) and (y=8x+(2t-3)) have equal slopes, what is the (y)-intercept of the second line?
C. (13)
समान ढाल से (t+1=8) और (t=7) है। दूसरी रेखा का (y)-अवरोध (2t-3=11) नहीं बल्कि (11) है। / Equal slopes give (t+1=8) and (t=7). The second line's (y)-intercept is (2t-3=11), so option (A) is correct.
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If (y=2x+(v-4)) and (y=(v+1)x+5) have the same (y)-intercept, what is the slope of the second line?
C. (10)
समान (y)-अवरोध से (v-4=5) और (v=9) है। दूसरी रेखा की ढाल (v+1=10) है। / Equal (y)-intercepts give (v-4=5) and (v=9). The slope of the second line is (v+1=10).
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In the line \(y=-\frac{3}{2}x+10\), how much should (x) increase to decrease (y) by (18)?
C. (12)
कमी \(\frac{3}{2}\Delta x\) होगी। \(\frac{3}{2}\Delta x=18\) से \(\Delta x=12\) मिलता है। / The decrease is \(\frac{3}{2}\Delta x\). From \(\frac{3}{2}\Delta x=18\), \(\Delta x=12\).
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If (y=(k+3)x+2) increases (y) by (16) when (x) increases by (2), what is (k)?
C. (5)
ढाल (k+3) है और (2(k+3)=16)। इसलिए (k+3=8) और (k=5) है। / The slope is (k+3) and (2(k+3)=16). Therefore (k+3=8) and (k=5).
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If (c=-6) and (m-c=14) in (y=mx+c), what is the slope?
C. (8)
(c=-6) रखने पर (m-(-6)=14) मिलता है। इसलिए (m+6=14) और (m=8) है। / Putting (c=-6) gives (m-(-6)=14). So (m+6=14) and (m=8).
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If (m=-2) and (2c+m=10) in (y=mx+c), what is the (y)-intercept?
C. (6)
(m=-2) रखने पर (2c-2=10) मिलता है। इससे (2c=12) और (c=6) है। / Putting (m=-2) gives (2c-2=10). Thus (2c=12) and (c=6).
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