Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 331-340 of 600 questions.
In the line (y=-3x+12), by how much must (x) increase for (y) to decrease by (21)?
B. (7)
ढाल (-3) है, इसलिए कमी \(3\Delta x\) होगी। \(3\Delta x=21\) से \(\Delta x=7\) मिलता है। / The slope is (-3), so the decrease is \(3\Delta x\). From \(3\Delta x=21\), \(\Delta x=7\).
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In the line \(y=\frac{5}{2}x-1\), how much should (x) increase to increase (y) by (20)?
B. (8)
परिवर्तन \(\frac{5}{2}\Delta x=20\) होगा। इससे \(\Delta x=8\) मिलता है। / The change is \(\frac{5}{2}\Delta x=20\). This gives \(\Delta x=8\).
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If (p=-4) and (q=9) in (y=px+q), which statement is correct?
B. रेखा घटती है और (y)-अवरोध धनात्मक हैThe line decreases and (y)-intercept is positive
(p=-4) ऋणात्मक ढाल देता है और (q=9) धनात्मक (y)-अवरोध देता है। इसलिए रेखा घटती है। / (p=-4) gives a negative slope and (q=9) gives a positive (y)-intercept. So the line decreases.
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If (2x+ay=16) has (y)-intercept (4), what is (a)?
C. (4)
(x=0) रखने पर (ay=16) और \(y=\frac{16}{a}\) मिलता है। \(\frac{16}{a}=4\) से (a=4) है। / Putting (x=0) gives (ay=16) and \(y=\frac{16}{a}\). From \(\frac{16}{a}=4\), (a=4).
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If (bx+4y=20) has slope (-3), what is (b)?
C. (12)
(4y=-bx+20) से ढाल \(-\frac{b}{4}\) है। \(-\frac{b}{4}=-3\) से (b=12) मिलता है। / From (4y=-bx+20), the slope is \(-\frac{b}{4}\). From \(-\frac{b}{4}=-3\), (b=12).
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The line (y=(n-5)x+(2n+1)) has (y)-intercept (11). What is its slope?
A. (0)
(2n+1=11) से (n=5) मिलता है। ढाल (n-5=0) है। / From (2n+1=11), (n=5). The slope is (n-5=0).
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The line (y=(r+4)x+(r-2)) has slope (1). What is its (y)-intercept?
A. ( -5 )
(r+4=1) से (r=-3) मिलता है। (y)-अवरोध (r-2=-5) है। / From (r+4=1), (r=-3). The (y)-intercept is (r-2=-5).
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Which line cuts the (y)-axis at ( (0,-6) ) and increases (y) by (10) when (x) increases by (2)?
A. (y=5x-6)
ढाल \(\frac{10}{2}=5\) है और (y)-अवरोध (-6) है। इसलिए रेखा (y=5x-6) है। / The slope is \(\frac{10}{2}=5\) and the (y)-intercept is (-6). So the line is (y=5x-6).
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Which line cuts the (y)-axis at ( (0,9) ) and decreases (y) by (12) when (x) increases by (3)?
B. (y=-4x+9)
ढाल \(-\frac{12}{3}=-4\) है और (y)-अवरोध (9) है। इसलिए (y=-4x+9) सही है। / The slope is \(-\frac{12}{3}=-4\) and the (y)-intercept is (9). So (y=-4x+9) is correct.
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If (y=(a+1)x+(a-7)) passes through the origin, what will be its slope?
C. (8)
मूल बिंदु से गुजरने के लिए (a-7=0) होगा। इसलिए (a=7) और ढाल (a+1=8) है। / To pass through the origin, (a-7=0). Thus (a=7) and the slope is (a+1=8).
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