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\(6x^2+17x+12\) का सही गुणनखंड रूप क्या है?
What is the correct factorised form of \(6x^2+17x+12\)?
#factorisation
#quadratic
#splitting middle term
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A ((2x+3)(3x+4))
B ((6x+3)(x+4))
C ((2x+4)(3x+3))
D ((x+3)(6x+4))
Explanation opens after your attempt
Correct Answer
A. ((2x+3)(3x+4))
Step 1
Concept
On multiplying we get \(6x^2+8x+9x+12=6x^2+17x+12\). Exam tip: check by adding the middle terms.
Step 2
Why this answer is correct
The correct answer is A. ((2x+3)(3x+4)). On multiplying we get \(6x^2+8x+9x+12=6x^2+17x+12\). Exam tip: check by adding the middle terms.
Step 3
Exam Tip
गुणा करने पर \(6x^2+8x+9x+12=6x^2+17x+12\) मिलता है। परीक्षा में बीच के पदों को जोड़कर जांचें।
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\(12a^2-7a-10\) के गुणनखंड कौन से हैं?
What are the factors of \(12a^2-7a-10\)?
#quadratic factorisation
#hard algebra
#signs
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A ((3a+2)(4a-5))
B ((3a-5)(4a+2))
C ((2a-5)(6a+2))
D ((4a-5)(3a+2))
Explanation opens after your attempt
Correct Answer
D. ((4a-5)(3a+2))
Step 1
Concept
Expanding ((4a-5)(3a+2)) gives \(12a^2+8a-15a-10\). Exam tip: add opposite-signed terms carefully.
Step 2
Why this answer is correct
The correct answer is D. ((4a-5)(3a+2)). Expanding ((4a-5)(3a+2)) gives \(12a^2+8a-15a-10\). Exam tip: add opposite-signed terms carefully.
Step 3
Exam Tip
((4a-5)(3a+2)) फैलाने पर \(12a^2+8a-15a-10\) मिलता है। परीक्षा में विपरीत चिन्हों वाले पदों का योग ध्यान से करें।
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\(x^2-13x+42\) को किस रूप में लिखा जाएगा?
In which form will \(x^2-13x+42\) be written?
#trinomial factorisation
#signs
#quadratic
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A ((x-6)(x-7))
B ((x+6)(x+7))
C ((x-3)(x-14))
D ((x+3)(x-14))
Explanation opens after your attempt
Correct Answer
A. ((x-6)(x-7))
Step 1
Concept
Since (-6-7=-13) and ((-6)(-7)=42). Exam tip: use two negative signs for positive last term and negative middle term.
Step 2
Why this answer is correct
The correct answer is A. ((x-6)(x-7)). Since (-6-7=-13) and ((-6)(-7)=42). Exam tip: use two negative signs for positive last term and negative middle term.
Step 3
Exam Tip
(-6-7=-13) और ((-6)(-7)=42) है। परीक्षा में धनात्मक अंतिम पद और ऋणात्मक मध्य पद के लिए दोनों चिन्ह ऋणात्मक लें।
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\(2x^2-11x+12\) के सही गुणनखंड कौन से हैं?
What are the correct factors of \(2x^2-11x+12\)?
#splitting middle term
#factorisation
#quadratic
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A ((2x-3)(x-4))
B ((2x-3)(x+4))
C ((2x-8)(x-3))
D ((x-3)(2x-4))
Explanation opens after your attempt
Correct Answer
A. ((2x-3)(x-4))
Step 1
Concept
((2x-3)(x-4)) gives \(2x^2-8x-3x+12\). Exam tip: confirm the middle term (-11x).
Step 2
Why this answer is correct
The correct answer is A. ((2x-3)(x-4)). ((2x-3)(x-4)) gives \(2x^2-8x-3x+12\). Exam tip: confirm the middle term (-11x).
Step 3
Exam Tip
((2x-3)(x-4)) से \(2x^2-8x-3x+12\) मिलता है। परीक्षा में मध्य पद (-11x) की पुष्टि करें।
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\(8x^2+2x-3\) का गुणनखंड रूप क्या है?
What is the factorised form of \(8x^2+2x-3\)?
#factorisation
#quadratic
#signs
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A ((4x+3)(2x-1))
B ((4x-3)(2x+1))
C ((8x-3)(x+1))
D ((2x-3)(4x+1))
Explanation opens after your attempt
Correct Answer
A. ((4x+3)(2x-1))
Step 1
Concept
((4x+3)(2x-1)) gives \(8x^2-4x+6x-3\). Exam tip: add opposite-signed terms correctly.
Step 2
Why this answer is correct
The correct answer is A. ((4x+3)(2x-1)). ((4x+3)(2x-1)) gives \(8x^2-4x+6x-3\). Exam tip: add opposite-signed terms correctly.
Step 3
Exam Tip
((4x+3)(2x-1)) से \(8x^2-4x+6x-3\) मिलता है। परीक्षा में विपरीत चिन्हों के पदों को सही जोड़ें।
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\(3y^2+14y+8\) को गुणनखंडित कीजिए।
Factorise \(3y^2+14y+8\).
#quadratic factorisation
#checking
#algebra
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A ((3y+2)(y+4))
B ((3y+4)(y+2))
C ((y+2)(3y+8))
D ((3y+8)(y+1))
Explanation opens after your attempt
Correct Answer
B. ((3y+4)(y+2))
Step 1
Concept
((3y+2)(y+4)) gives (12y+2y), while ((3y+4)(y+2)) is correct. Exam tip: verify by expansion.
Step 2
Why this answer is correct
The correct answer is B. ((3y+4)(y+2)). ((3y+2)(y+4)) gives (12y+2y), while ((3y+4)(y+2)) is correct. Exam tip: verify by expansion.
Step 3
Exam Tip
((3y+2)(y+4)) से (14y) नहीं बल्कि (12y+2y) मिलता है, जबकि ((3y+4)(y+2)) सही है। परीक्षा में फैलाकर जांचें।
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\(2x^2+7xy+3y^2\) का गुणनखंड रूप क्या होगा?
What will be the factorised form of \(2x^2+7xy+3y^2\)?
#two variable quadratic
#factorisation
#middle term
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A ((2x+y)(x+3y))
B ((2x+3y)(x+y))
C ((x+y)(2x+3y))
D ((2x-y)(x-3y))
Explanation opens after your attempt
Correct Answer
B. ((2x+3y)(x+y))
Step 1
Concept
((2x+3y)(x+y)) gives \(2x^2+2xy+3xy+3y^2\). Exam tip: check the sum of (xy)-terms.
Step 2
Why this answer is correct
The correct answer is B. ((2x+3y)(x+y)). ((2x+3y)(x+y)) gives \(2x^2+2xy+3xy+3y^2\). Exam tip: check the sum of (xy)-terms.
Step 3
Exam Tip
((2x+3y)(x+y)) से \(2x^2+2xy+3xy+3y^2\) मिलता है। परीक्षा में (xy) पदों का योग जांचें।
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\(x^2+2x-24\) का गुणनखंड रूप क्या है?
What is the factorised form of \(x^2+2x-24\)?
#trinomial factorisation
#signs
#quadratic
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A ((x+6)(x-4))
B ((x-6)(x+4))
C ((x+8)(x-3))
D ((x-8)(x+3))
Explanation opens after your attempt
Correct Answer
A. ((x+6)(x-4))
Step 1
Concept
(6+(-4)=2) and (6(-4)=-24). Exam tip: choose opposite signs for a negative last term.
Step 2
Why this answer is correct
The correct answer is A. ((x+6)(x-4)). (6+(-4)=2) and (6(-4)=-24). Exam tip: choose opposite signs for a negative last term.
Step 3
Exam Tip
(6+(-4)=2) और (6(-4)=-24) है। परीक्षा में ऋणात्मक अंतिम पद के लिए विपरीत चिन्ह चुनें।
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\(5x^2+13x-6\) के गुणनखंड कौन से हैं?
What are the factors of \(5x^2+13x-6\)?
#quadratic factorisation
#splitting
#checking
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A ((5x-2)(x+3))
B ((5x+3)(x-2))
C ((5x-3)(x+2))
D ((x-2)(5x+3))
Explanation opens after your attempt
Correct Answer
A. ((5x-2)(x+3))
Step 1
Concept
((5x-2)(x+3)) gives \(5x^2+15x-2x-6\). Exam tip: expand to check the middle term (13x).
Step 2
Why this answer is correct
The correct answer is A. ((5x-2)(x+3)). ((5x-2)(x+3)) gives \(5x^2+15x-2x-6\). Exam tip: expand to check the middle term (13x).
Step 3
Exam Tip
((5x-2)(x+3)) से \(5x^2+15x-2x-6\) मिलता है। परीक्षा में फैलाकर मध्य पद (13x) जांचें।
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\(7x^2-29x+12\) का सही गुणनखंड रूप क्या है?
What is the correct factorised form of \(7x^2-29x+12\)?
#hard quadratic
#factorisation
#signs
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A ((7x-3)(x-4))
B ((7x-4)(x-3))
C ((7x-12)(x-1))
D ((x-4)(7x-3))
Explanation opens after your attempt
Correct Answer
D. ((x-4)(7x-3))
Step 1
Concept
((x-4)(7x-3)) gives \(7x^2-3x-28x+12\). Exam tip: add both negative terms carefully.
Step 2
Why this answer is correct
The correct answer is D. ((x-4)(7x-3)). ((x-4)(7x-3)) gives \(7x^2-3x-28x+12\). Exam tip: add both negative terms carefully.
Step 3
Exam Tip
((x-4)(7x-3)) से \(7x^2-3x-28x+12\) मिलता है। परीक्षा में दोनों ऋणात्मक पदों का योग ध्यान से करें।
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\(3x^2-14x+8\) के सही गुणनखंड कौन से हैं?
What are the correct factors of \(3x^2-14x+8\)?
#quadratic factorisation
#middle term
#signs
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+10 Time+ 10 sec extra
? Hint Small clue
A ((3x-2)(x-4))
B ((3x-8)(x-1))
C ((x-2)(3x-4))
D ((3x+2)(x-4))
Explanation opens after your attempt
Correct Answer
A. ((3x-2)(x-4))
Step 1
Concept
((3x-2)(x-4)) gives \(3x^2-12x-2x+8\). Exam tip: check the middle term (-14x).
Step 2
Why this answer is correct
The correct answer is A. ((3x-2)(x-4)). ((3x-2)(x-4)) gives \(3x^2-12x-2x+8\). Exam tip: check the middle term (-14x).
Step 3
Exam Tip
((3x-2)(x-4)) से \(3x^2-12x-2x+8\) मिलता है। परीक्षा में मध्य पद (-14x) जांचें।
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\(10x^2+x-3\) का सही गुणनखंड रूप क्या है?
What is the correct factorised form of \(10x^2+x-3\)?
#quadratic factorisation
#signs
#checking
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A ((5x+3)(2x-1))
B ((5x-3)(2x+1))
C ((10x-3)(x+1))
D ((2x+3)(5x-1))
Explanation opens after your attempt
Correct Answer
A. ((5x+3)(2x-1))
Step 1
Concept
((5x+3)(2x-1)) gives \(10x^2-5x+6x-3\). Exam tip: identify the small difference for the middle term (x).
Step 2
Why this answer is correct
The correct answer is A. ((5x+3)(2x-1)). ((5x+3)(2x-1)) gives \(10x^2-5x+6x-3\). Exam tip: identify the small difference for the middle term (x).
Step 3
Exam Tip
((5x+3)(2x-1)) से \(10x^2-5x+6x-3\) मिलता है। परीक्षा में मध्य पद (x) के लिए छोटे अंतर को पहचानें।
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\(15x^2-2x-8\) के गुणनखंड कौन से हैं?
What are the factors of \(15x^2-2x-8\)?
#hard quadratic
#factorisation
#middle term
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? Hint Small clue
A ((3x+2)(5x-4))
B ((3x-2)(5x+4))
C ((15x+4)(x-2))
D ((5x+2)(3x-4))
Explanation opens after your attempt
Correct Answer
D. ((5x+2)(3x-4))
Step 1
Concept
((5x+2)(3x-4)) gives \(15x^2-20x+6x-8\). Exam tip: choose the pair that gives (-2x), not (-14x).
Step 2
Why this answer is correct
The correct answer is D. ((5x+2)(3x-4)). ((5x+2)(3x-4)) gives \(15x^2-20x+6x-8\). Exam tip: choose the pair that gives (-2x), not (-14x).
Step 3
Exam Tip
((5x+2)(3x-4)) से \(15x^2-20x+6x-8\) मिलता है। परीक्षा में (-14x) नहीं बल्कि (-2x) के लिए सही जोड़ी चुनें।
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\(2a^2+ab-15b^2\) का गुणनखंड रूप क्या होगा?
What will be the factorised form of \(2a^2+ab-15b^2\)?
#two variable quadratic
#factorisation
#signs
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A ((2a-5b)(a+3b))
B ((2a+5b)(a-3b))
C ((a+5b)(2a-3b))
D ((2a-3b)(a+5b))
Explanation opens after your attempt
Correct Answer
A. ((2a-5b)(a+3b))
Step 1
Concept
((2a-5b)(a+3b)) gives \(2a^2+6ab-5ab-15b^2\). Exam tip: check the sum of (ab)-terms.
Step 2
Why this answer is correct
The correct answer is A. ((2a-5b)(a+3b)). ((2a-5b)(a+3b)) gives \(2a^2+6ab-5ab-15b^2\). Exam tip: check the sum of (ab)-terms.
Step 3
Exam Tip
((2a-5b)(a+3b)) से \(2a^2+6ab-5ab-15b^2\) मिलता है। परीक्षा में (ab) पदों का योग जांचें।
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