यदि किसी श्रेणी का (n)वाँ पद \(a_n=6n-5\) है तो (18)वाँ पद क्या होगा?
If the (n)th term of a sequence is \(a_n=6n-5\), what will be the (18)th term?
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A (101)
B (103)
C (105)
D (107)
Explanation opens after your attempt
Step 1
Concept
Putting (n=18) gives \(a_{18}=108-5=103\). In exams, substitute the term number directly in the formula.
Step 2
Why this answer is correct
The correct answer is B. (103). Putting (n=18) gives \(a_{18}=108-5=103\). In exams, substitute the term number directly in the formula.
Step 3
Exam Tip
(n=18) रखने पर \(a_{18}=108-5=103\) मिलता है। परीक्षा में पद संख्या को सीधे सूत्र में रखें।
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श्रेणी \(8,15,24,35,48,\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(8,15,24,35,48,\ldots\)?
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A \(n^2+4n+3\)
B \(n^2+5n+2\)
C \(2n^2+3n+3\)
D \(n^2+3n+4\)
Explanation opens after your attempt
Correct Answer
A. \(n^2+4n+3\)
Step 1
Concept
The given terms are formed by \(n^2+4n+3\). Testing options on the first three terms is a fast method.
Step 2
Why this answer is correct
The correct answer is A. \(n^2+4n+3\). The given terms are formed by \(n^2+4n+3\). Testing options on the first three terms is a fast method.
Step 3
Exam Tip
दिए पद \(n^2+4n+3\) से सही बनते हैं। पहले तीन पदों पर विकल्प जांचना तेज तरीका है।
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यदि \(a_n=4n^2-3n+2\) है तो \(a_7-a_4\) का मान क्या है?
If \(a_n=4n^2-3n+2\), what is the value of \(a_7-a_4\)?
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A (117)
B (119)
C (121)
D (123)
Explanation opens after your attempt
Step 1
Concept
\(a_7=177\) and \(a_4=54\), so the difference is (123). Find both terms separately first.
Step 2
Why this answer is correct
The correct answer is D. (123). \(a_7=177\) and \(a_4=54\), so the difference is (123). Find both terms separately first.
Step 3
Exam Tip
\(a_7=177\) और \(a_4=54\) है इसलिए अंतर (123) है। पहले दोनों पद अलग निकालें।
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श्रेणी \(3,9,18,30,45,\ldots\) का (n)वाँ पद क्या है?
What is the (n)th term of the sequence \(3,9,18,30,45,\ldots\)?
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A \(3n^2\)
B (n(n+2))
C (\frac{3n(n+1)}{2})
D (\frac{n(n+3)}{2})
Explanation opens after your attempt
Correct Answer
C. (\frac{3n(n+1)}{2})
Step 1
Concept
The terms are (3) times triangular numbers. Recognize patterns involving (n(n+1)).
Step 2
Why this answer is correct
The correct answer is C. (\frac{3n(n+1)}{2}). The terms are (3) times triangular numbers. Recognize patterns involving (n(n+1)).
Step 3
Exam Tip
पद (3) गुणा त्रिभुज संख्याओं जैसे हैं। (n(n+1)) वाले पैटर्न को पहचानें।
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एक रैखिक श्रेणी में \(a_5=23\) और \(a_{12}=58\) है तो \(a_{20}\) क्या होगा?
In a linear sequence, \(a_5=23\) and \(a_{12}=58\). What will be \(a_{20}\)?
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A (98)
B (96)
C (100)
D (102)
Explanation opens after your attempt
Step 1
Concept
The increase over (7) positions is (35), so the difference is (5). The formula \(a_n=5n-2\) gives \(a_{20}=98\).
Step 2
Why this answer is correct
The correct answer is A. (98). The increase over (7) positions is (35), so the difference is (5). The formula \(a_n=5n-2\) gives \(a_{20}=98\).
Step 3
Exam Tip
(7) स्थानों में वृद्धि (35) है इसलिए अंतर (5) है। सूत्र \(a_n=5n-2\) से \(a_{20}=98\) मिलता है।
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श्रेणी \(\frac{4}{7},\frac{7}{10},\frac{10}{13},\frac{13}{16},\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(\frac{4}{7},\frac{7}{10},\frac{10}{13},\frac{13}{16},\ldots\)?
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A \(\frac{3n+2}{3n+5}\)
B \(\frac{n+3}{n+6}\)
C \(\frac{3n+4}{3n+7}\)
D \(\frac{3n+1}{3n+4}\)
Explanation opens after your attempt
Correct Answer
D. \(\frac{3n+1}{3n+4}\)
Step 1
Concept
The numerator \(4,7,10,\ldots\) gives (3n+1), and the denominator \(7,10,13,\ldots\) gives (3n+4). Observe numerator and denominator separately.
Step 2
Why this answer is correct
The correct answer is D. \(\frac{3n+1}{3n+4}\). The numerator \(4,7,10,\ldots\) gives (3n+1), and the denominator \(7,10,13,\ldots\) gives (3n+4). Observe numerator and denominator separately.
Step 3
Exam Tip
अंश \(4,7,10,\ldots\) से (3n+1) और हर \(7,10,13,\ldots\) से (3n+4) है। भिन्नों में अंश और हर अलग देखें।
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यदि \(a_n=3n^2+2\) है तो (149) कौन सा पद है?
If \(a_n=3n^2+2\), which term is (149)?
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A (5)वाँ / (5)th
B (6)वाँ / (6)th
C (7)वाँ / (7)th
D (8)वाँ / (8)th
Explanation opens after your attempt
Correct Answer
C. (7)वाँ / (7)th
Step 1
Concept
From \(3n^2+2=149\), \(n^2=49\) and (n=7). Take the positive value for the term number.
Step 2
Why this answer is correct
The correct answer is C. (7)वाँ / (7)th. From \(3n^2+2=149\), \(n^2=49\) and (n=7). Take the positive value for the term number.
Step 3
Exam Tip
\(3n^2+2=149\) से \(n^2=49\) और (n=7) मिलता है। पद संख्या के लिए धनात्मक मान लें।
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यदि \(a_n=40-5n\) है तो पहला ऋणात्मक पद कौन सा होगा?
If \(a_n=40-5n\), which will be the first negative term?
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A (9)वाँ पद / (9)th term
B (8)वाँ पद / (8)th term
C (10)वाँ पद / (10)th term
D (11)वाँ पद / (11)th term
Explanation opens after your attempt
Correct Answer
A. (9)वाँ पद / (9)th term
Step 1
Concept
From (40-5n<0), we get (n>8). So the first natural value is (9).
Step 2
Why this answer is correct
The correct answer is A. (9)वाँ पद / (9)th term. From (40-5n<0), we get (n>8). So the first natural value is (9).
Step 3
Exam Tip
(40-5n<0) से (n>8) मिलता है। इसलिए पहला प्राकृतिक मान (9) है।
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यदि \(a_n=kn^2-n\) और \(a_6=210\) है तो \(a_4\) का मान क्या होगा?
If \(a_n=kn^2-n\) and \(a_6=210\), what will be the value of \(a_4\)?
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A (84)
B (88)
C (90)
D (92)
Explanation opens after your attempt
Step 1
Concept
From (36k-6=210), (k=6). Then \(a_4=6\cdot16-4=92\).
Step 2
Why this answer is correct
The correct answer is D. (92). From (36k-6=210), (k=6). Then \(a_4=6\cdot16-4=92\).
Step 3
Exam Tip
(36k-6=210) से (k=6) मिलता है। फिर \(a_4=6\cdot16-4=92\) है।
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श्रेणी \(2,11,28,53,86,\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(2,11,28,53,86,\ldots\)?
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A \(3n^2-2n+1\)
B \(4n^2-2n\)
C \(4n^2-3n+1\)
D \(2n^2+5n-5\)
Explanation opens after your attempt
Correct Answer
C. \(4n^2-3n+1\)
Step 1
Concept
The second difference is (8), so the coefficient of \(n^2\) is (4). Substitution gives \(4n^2-3n+1\).
Step 2
Why this answer is correct
The correct answer is C. \(4n^2-3n+1\). The second difference is (8), so the coefficient of \(n^2\) is (4). Substitution gives \(4n^2-3n+1\).
Step 3
Exam Tip
दूसरा अंतर (8) है इसलिए \(n^2\) का गुणांक (4) होगा। मान रखने पर \(4n^2-3n+1\) सही है।
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यदि \(a_n=2^n+n\) है तो \(a_5\) का मान क्या है?
If \(a_n=2^n+n\), what is the value of \(a_5\)?
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A (35)
B (37)
C (39)
D (41)
Explanation opens after your attempt
Step 1
Concept
\(2^5=32\) and (32+5=37). Do the exponent and addition separately.
Step 2
Why this answer is correct
The correct answer is B. (37). \(2^5=32\) and (32+5=37). Do the exponent and addition separately.
Step 3
Exam Tip
\(2^5=32\) और (32+5=37) है। घात और जोड़ को अलग-अलग करें।
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यदि \(a_n=pn+q\), \(a_4+a_7=64\) और \(a_5+a_8=76\) है तो \(a_{10}\) क्या होगा?
If \(a_n=pn+q\), \(a_4+a_7=64\), and \(a_5+a_8=76\), what will be \(a_{10}\)?
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A (59)
B (61)
C (63)
D (65)
Explanation opens after your attempt
Step 1
Concept
Subtracting the two sums gives (2p=12), so (p=6). Then (q=-1) and \(a_{10}=59\).
Step 2
Why this answer is correct
The correct answer is A. (59). Subtracting the two sums gives (2p=12), so (p=6). Then (q=-1) and \(a_{10}=59\).
Step 3
Exam Tip
दोनों योग घटाने पर (2p=12) इसलिए (p=6) है। फिर (q=-1) और \(a_{10}=59\) मिलता है।
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श्रेणी \(7,17,31,49,71,\ldots\) का (n)वाँ पद क्या है?
What is the (n)th term of the sequence \(7,17,31,49,71,\ldots\)?
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A \(2n^2+3n+2\)
B \(n^2+6n\)
C \(3n^2+n+3\)
D \(2n^2+4n+1\)
Explanation opens after your attempt
Correct Answer
D. \(2n^2+4n+1\)
Step 1
Concept
The given terms are formed by \(2n^2+4n+1\). Start eliminating wrong options from the first term itself.
Step 2
Why this answer is correct
The correct answer is D. \(2n^2+4n+1\). The given terms are formed by \(2n^2+4n+1\). Start eliminating wrong options from the first term itself.
Step 3
Exam Tip
दिए पद \(2n^2+4n+1\) से बनते हैं। पहले पद से ही गलत विकल्प हटाने शुरू करें।
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यदि (a_n=\frac{n(n+5)}{3}) है तो \(a_6\) का मान क्या है?
If (a_n=\frac{n(n+5)}{3}), what is the value of \(a_6\)?
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A (18)
B (20)
C (22)
D (24)
Explanation opens after your attempt
Step 1
Concept
\(a_6=\frac{6\cdot11}{3}=22\). Checking cancellation before multiplying saves time.
Step 2
Why this answer is correct
The correct answer is C. (22). \(a_6=\frac{6\cdot11}{3}=22\). Checking cancellation before multiplying saves time.
Step 3
Exam Tip
\(a_6=\frac{6\cdot11}{3}=22\) है। गुणा करने से पहले कटौती देखना समय बचाता है।
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यदि \(a_n=3n^2+5n\) है तो \(a_{n+1}-a_n\) क्या होगा?
If \(a_n=3n^2+5n\), what is \(a_{n+1}-a_n\)?
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A (6n+6)
B (6n+8)
C (3n+8)
D (6n+5)
Explanation opens after your attempt
Step 1
Concept
Putting (n+1) in \(a_{n+1}\) and subtracting gives (6n+8). Do not forget brackets while expanding.
Step 2
Why this answer is correct
The correct answer is B. (6n+8). Putting (n+1) in \(a_{n+1}\) and subtracting gives (6n+8). Do not forget brackets while expanding.
Step 3
Exam Tip
\(a_{n+1}\) में (n+1) रखकर घटाने पर (6n+8) मिलता है। विस्तार में कोष्ठक न भूलें।
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श्रेणी \(0,5,16,33,56,\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(0,5,16,33,56,\ldots\)?
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A \(3n^2-4n+1\)
B \(2n^2+n-3\)
C \(3n^2-3n\)
D \(n^2+4n-5\)
Explanation opens after your attempt
Correct Answer
A. \(3n^2-4n+1\)
Step 1
Concept
The second difference is (6), so the coefficient of \(n^2\) is (3). Checking gives \(3n^2-4n+1\).
Step 2
Why this answer is correct
The correct answer is A. \(3n^2-4n+1\). The second difference is (6), so the coefficient of \(n^2\) is (3). Checking gives \(3n^2-4n+1\).
Step 3
Exam Tip
दूसरा अंतर (6) है इसलिए \(n^2\) का गुणांक (3) होगा। जांचने पर \(3n^2-4n+1\) मिलता है।
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यदि \(a_n=7n-9\) है तो (131) कौन सा पद है?
If \(a_n=7n-9\), which term is (131)?
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A (17)वाँ / (17)th
B (18)वाँ / (18)th
C (19)वाँ / (19)th
D (20)वाँ / (20)th
Explanation opens after your attempt
Correct Answer
D. (20)वाँ / (20)th
Step 1
Concept
From (7n-9=131), (7n=140) and (n=20). Form an equation to find the term number.
Step 2
Why this answer is correct
The correct answer is D. (20)वाँ / (20)th. From (7n-9=131), (7n=140) and (n=20). Form an equation to find the term number.
Step 3
Exam Tip
(7n-9=131) से (7n=140) और (n=20) है। समीकरण बनाकर पद संख्या निकालें।
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यदि \(a_n=n^2-6n+13\) है तो सबसे छोटा पद मान क्या है?
If \(a_n=n^2-6n+13\), what is the smallest term value?
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A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
At (n=3), \(a_3=4\) is the smallest. In a quadratic formula, check values near the vertex.
Step 2
Why this answer is correct
The correct answer is B. (4). At (n=3), \(a_3=4\) is the smallest. In a quadratic formula, check values near the vertex.
Step 3
Exam Tip
(n=3) पर \(a_3=4\) सबसे छोटा आता है। वर्गीय सूत्र में शीर्ष के आसपास के मान जांचें।
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श्रेणी \(\frac{1}{3},\frac{4}{8},\frac{9}{15},\frac{16}{24},\ldots\) का सरल (n)वाँ पद क्या है?
What is the simplified (n)th term of the sequence \(\frac{1}{3},\frac{4}{8},\frac{9}{15},\frac{16}{24},\ldots\)?
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A \(\frac{n}{n+1}\)
B \(\frac{n^2}{n+2}\)
C \(\frac{n}{n+2}\)
D \(\frac{n+1}{n+3}\)
Explanation opens after your attempt
Correct Answer
C. \(\frac{n}{n+2}\)
Step 1
Concept
The numerator is \(n^2\) and the denominator is (n(n+2)). Simplifying gives \(\frac{n}{n+2}\).
Step 2
Why this answer is correct
The correct answer is C. \(\frac{n}{n+2}\). The numerator is \(n^2\) and the denominator is (n(n+2)). Simplifying gives \(\frac{n}{n+2}\).
Step 3
Exam Tip
अंश \(n^2\) और हर (n(n+2)) है। सरल करने पर \(\frac{n}{n+2}\) मिलता है।
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यदि \(a_n=5\cdot3^{n-1}-2\) है तो \(a_4\) क्या होगा?
If \(a_n=5\cdot3^{n-1}-2\), what will be \(a_4\)?
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A (131)
B (133)
C (135)
D (137)
Explanation opens after your attempt
Step 1
Concept
\(a_4=5\cdot3^3-2=133\). Write the exponent (n-1) carefully.
Step 2
Why this answer is correct
The correct answer is B. (133). \(a_4=5\cdot3^3-2=133\). Write the exponent (n-1) carefully.
Step 3
Exam Tip
\(a_4=5\cdot3^3-2=133\) है। (n-1) वाली घात को सावधानी से लिखें।
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श्रेणी \(4,7,14,25,40,\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(4,7,14,25,40,\ldots\)?
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A \(n^2+2n+1\)
B \(2n^2-2n+4\)
C \(n^2+3n\)
D \(2n^2-3n+5\)
Explanation opens after your attempt
Correct Answer
D. \(2n^2-3n+5\)
Step 1
Concept
The given terms match \(2n^2-3n+5\). Use second differences to identify a quadratic form.
Step 2
Why this answer is correct
The correct answer is D. \(2n^2-3n+5\). The given terms match \(2n^2-3n+5\). Use second differences to identify a quadratic form.
Step 3
Exam Tip
दिए पद \(2n^2-3n+5\) से सही मिलते हैं। दूसरे अंतर से वर्गीय रूप पहचानें।
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यदि \(a_n=rn+s\), \(a_3=14\) और \(a_{10}=49\) है तो \(a_{15}\) क्या होगा?
If \(a_n=rn+s\), \(a_3=14\), and \(a_{10}=49\), what will be \(a_{15}\)?
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A (69)
B (74)
C (79)
D (84)
Explanation opens after your attempt
Step 1
Concept
The increase over (7) positions is (35), so (r=5). The formula \(a_n=5n-1\) gives \(a_{15}=74\).
Step 2
Why this answer is correct
The correct answer is B. (74). The increase over (7) positions is (35), so (r=5). The formula \(a_n=5n-1\) gives \(a_{15}=74\).
Step 3
Exam Tip
(7) स्थानों में वृद्धि (35) है इसलिए (r=5) है। सूत्र \(a_n=5n-1\) से \(a_{15}=74\) मिलता है।
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यदि \(a_n=4n^2-1\) है तो (100) से बड़ा पहला पद कौन सा होगा?
If \(a_n=4n^2-1\), which is the first term greater than (100)?
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A (4)वाँ पद / (4)th term
B (5)वाँ पद / (5)th term
C (6)वाँ पद / (6)th term
D (7)वाँ पद / (7)th term
Explanation opens after your attempt
Correct Answer
C. (6)वाँ पद / (6)th term
Step 1
Concept
From \(4n^2-1>100\), we get \(n^2>25.25\). The first natural value is (6).
Step 2
Why this answer is correct
The correct answer is C. (6)वाँ पद / (6)th term. From \(4n^2-1>100\), we get \(n^2>25.25\). The first natural value is (6).
Step 3
Exam Tip
\(4n^2-1>100\) से \(n^2>25.25\) मिलता है। पहला प्राकृतिक मान (6) है।
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यदि (a_n=(-1)^n(n+2)) है तो \(a_6+a_7\) का मान क्या होगा?
If (a_n=(-1)^n(n+2)), what will be the value of \(a_6+a_7\)?
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A (-1)
B (1)
C (-17)
D (17)
Explanation opens after your attempt
Step 1
Concept
\(a_6=8\) and \(a_7=-9\), so the sum is (-1). In sign-changing formulas, check even and odd values.
Step 2
Why this answer is correct
The correct answer is A. (-1). \(a_6=8\) and \(a_7=-9\), so the sum is (-1). In sign-changing formulas, check even and odd values.
Step 3
Exam Tip
\(a_6=8\) और \(a_7=-9\) है इसलिए योग (-1) है। चिह्न बदलने वाले सूत्रों में सम-विषम जांचें।
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यदि \(a_n=n^3\) है तो \(a_n-a_{n-1}\) का सूत्र क्या होगा?
If \(a_n=n^3\), what is the formula for \(a_n-a_{n-1}\)?
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A \(3n^2+3n+1\)
B \(3n^2-1\)
C \(n^2+n+1\)
D \(3n^2-3n+1\)
Explanation opens after your attempt
Correct Answer
D. \(3n^2-3n+1\)
Step 1
Concept
(n-3 -(n-1)3 =3n-2 -3n+1). Always put (n-1) in the previous term.
Step 2
Why this answer is correct
The correct answer is D. \(3n^2-3n+1\). (n-3 -(n-1)3 =3n-2 -3n+1). Always put (n-1) in the previous term.
Step 3
Exam Tip
(n-3 -(n-1)3 =3n-2 -3n+1) होता है। पिछले पद में (n-1) अवश्य रखें।
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यदि \(a_n=2n^2+kn+3\) और \(a_3=30\) है तो \(a_5\) का मान क्या होगा?
If \(a_n=2n^2+kn+3\) and \(a_3=30\), what will be the value of \(a_5\)?
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A (64)
B (68)
C (72)
D (76)
Explanation opens after your attempt
Step 1
Concept
From (18+3k+3=30), (k=3). Then \(a_5=50+15+3=68\).
Step 2
Why this answer is correct
The correct answer is B. (68). From (18+3k+3=30), (k=3). Then \(a_5=50+15+3=68\).
Step 3
Exam Tip
(18+3k+3=30) से (k=3) मिलता है। फिर \(a_5=50+15+3=68\) है।
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श्रेणी \(6,20,42,72,110,\ldots\) का (n)वाँ पद क्या है?
What is the (n)th term of the sequence \(6,20,42,72,110,\ldots\)?
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A \(3n^2+3n\)
B \(4n^2+n+1\)
C \(4n^2+2n\)
D \(2n^2+6n-2\)
Explanation opens after your attempt
Correct Answer
C. \(4n^2+2n\)
Step 1
Concept
The given terms are formed by \(4n^2+2n\). The second difference (8) indicates coefficient (4).
Step 2
Why this answer is correct
The correct answer is C. \(4n^2+2n\). The given terms are formed by \(4n^2+2n\). The second difference (8) indicates coefficient (4).
Step 3
Exam Tip
दिए पद \(4n^2+2n\) से बनते हैं। दूसरे अंतर (8) से गुणांक (4) का संकेत मिलता है।
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यदि (a_n=(n+1)(n+3)) है तो (80) कौन सा पद है?
If (a_n=(n+1)(n+3)), which term is (80)?
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A (7)वाँ / (7)th
B (8)वाँ / (8)th
C (9)वाँ / (9)th
D (10)वाँ / (10)th
Explanation opens after your attempt
Correct Answer
A. (7)वाँ / (7)th
Step 1
Concept
Putting (n=7) in ((n+1)(n+3)=80) gives \(8\cdot10=80\). Test the options quickly.
Step 2
Why this answer is correct
The correct answer is A. (7)वाँ / (7)th. Putting (n=7) in ((n+1)(n+3)=80) gives \(8\cdot10=80\). Test the options quickly.
Step 3
Exam Tip
((n+1)(n+3)=80) में (n=7) रखने पर \(8\cdot10=80\) मिलता है। विकल्पों को जल्दी जांचें।
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श्रेणी \(\frac{5}{6},\frac{9}{11},\frac{13}{16},\frac{17}{21},\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(\frac{5}{6},\frac{9}{11},\frac{13}{16},\frac{17}{21},\ldots\)?
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A \(\frac{4n+2}{5n+1}\)
B \(\frac{5n}{6n}\)
C \(\frac{4n+1}{5n+2}\)
D \(\frac{4n+1}{5n+1}\)
Explanation opens after your attempt
Correct Answer
D. \(\frac{4n+1}{5n+1}\)
Step 1
Concept
The numerator \(5,9,13,\ldots\) gives (4n+1), and the denominator \(6,11,16,\ldots\) gives (5n+1). Make separate rules for both sequences.
Step 2
Why this answer is correct
The correct answer is D. \(\frac{4n+1}{5n+1}\). The numerator \(5,9,13,\ldots\) gives (4n+1), and the denominator \(6,11,16,\ldots\) gives (5n+1). Make separate rules for both sequences.
Step 3
Exam Tip
अंश \(5,9,13,\ldots\) से (4n+1) और हर \(6,11,16,\ldots\) से (5n+1) है। दोनों श्रेणियों का अलग नियम बनाएं।
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यदि \(a_n=n^2+2n+5\) है तो \(a_9-a_1\) का मान क्या है?
If \(a_n=n^2+2n+5\), what is the value of \(a_9-a_1\)?
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A (94)
B (96)
C (98)
D (100)
Explanation opens after your attempt
Step 1
Concept
\(a_9=104\) and \(a_1=8\), so the difference is (96). Find the smaller term correctly first.
Step 2
Why this answer is correct
The correct answer is B. (96). \(a_9=104\) and \(a_1=8\), so the difference is (96). Find the smaller term correctly first.
Step 3
Exam Tip
\(a_9=104\) और \(a_1=8\) है इसलिए अंतर (96) है। पहले छोटे पद को सही निकालें।
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यदि \(a_n=an+b\), \(a_2+a_9=54\) और \(a_4+a_{11}=78\) है तो \(a_{12}\) क्या होगा?
If \(a_n=an+b\), \(a_2+a_9=54\), and \(a_4+a_{11}=78\), what will be \(a_{12}\)?
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A (60)
B (63)
C (66)
D (69)
Explanation opens after your attempt
Step 1
Concept
Subtracting the two sums gives (4a=24), so (a=6). Then (b=-6) and \(a_{12}=66\).
Step 2
Why this answer is correct
The correct answer is C. (66). Subtracting the two sums gives (4a=24), so (a=6). Then (b=-6) and \(a_{12}=66\).
Step 3
Exam Tip
दोनों योग घटाने पर (4a=24) इसलिए (a=6) है। फिर (b=-6) और \(a_{12}=66\) मिलता है।
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श्रेणी \(10,21,36,55,78,\ldots\) का (n)वाँ पद क्या है?
What is the (n)th term of the sequence \(10,21,36,55,78,\ldots\)?
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A \(2n^2+5n+3\)
B \(3n^2+2n+5\)
C \(n^2+8n+1\)
D \(2n^2+4n+4\)
Explanation opens after your attempt
Correct Answer
A. \(2n^2+5n+3\)
Step 1
Concept
The second difference is (4), so the coefficient of \(n^2\) is (2). Substitution gives \(2n^2+5n+3\).
Step 2
Why this answer is correct
The correct answer is A. \(2n^2+5n+3\). The second difference is (4), so the coefficient of \(n^2\) is (2). Substitution gives \(2n^2+5n+3\).
Step 3
Exam Tip
दूसरा अंतर (4) है इसलिए \(n^2\) का गुणांक (2) होगा। मान रखने पर \(2n^2+5n+3\) सही है।
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यदि \(a_n=100-7n\) है तो (30) से छोटा पहला पद कौन सा है?
If \(a_n=100-7n\), which is the first term less than (30)?
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A (8)वाँ पद / (8)th term
B (9)वाँ पद / (9)th term
C (10)वाँ पद / (10)th term
D (11)वाँ पद / (11)th term
Explanation opens after your attempt
Correct Answer
D. (11)वाँ पद / (11)th term
Step 1
Concept
From (100-7n<30), we get (n>10). The first natural value is (11).
Step 2
Why this answer is correct
The correct answer is D. (11)वाँ पद / (11)th term. From (100-7n<30), we get (n>10). The first natural value is (11).
Step 3
Exam Tip
(100-7n<30) से (n>10) मिलता है। पहला प्राकृतिक मान (11) है।
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यदि \(a_n=\frac{2n^2+1}{n+1}\) है तो \(a_4\) का मान क्या है?
If \(a_n=\frac{2n^2+1}{n+1}\), what is the value of \(a_4\)?
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A \(\frac{31}{5}\)
B \(\frac{33}{5}\)
C \(\frac{35}{5}\)
D \(\frac{37}{5}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{33}{5}\)
Step 1
Concept
Putting (n=4) gives \(\frac{33}{5}\). Simplify numerator and denominator separately in a fraction.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{33}{5}\). Putting (n=4) gives \(\frac{33}{5}\). Simplify numerator and denominator separately in a fraction.
Step 3
Exam Tip
(n=4) रखने पर \(\frac{33}{5}\) मिलता है। भिन्न में अंश और हर अलग सरल करें।
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श्रेणी \(2,6,14,30,62,\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(2,6,14,30,62,\ldots\)?
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A \(2^n-2\)
B \(2^{n+1}\)
C \(2^{n+1}-2\)
D \(2^{n+2}-6\)
Explanation opens after your attempt
Correct Answer
C. \(2^{n+1}-2\)
Step 1
Concept
The terms are \(4-2,8-2,16-2,\ldots\). In exponential patterns, look for fixed subtraction.
Step 2
Why this answer is correct
The correct answer is C. \(2^{n+1}-2\). The terms are \(4-2,8-2,16-2,\ldots\). In exponential patterns, look for fixed subtraction.
Step 3
Exam Tip
पद \(4-2,8-2,16-2,\ldots\) हैं। घातीय पैटर्न में स्थिर घटाव देखें।
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यदि \(a_n=n^2+mn+4\) और \(a_2+a_4=46\) है तो (m) का मान क्या है?
If \(a_n=n^2+mn+4\) and \(a_2+a_4=46\), what is the value of (m)?
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A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(a_2=8+2m\) and \(a_4=20+4m\). From (28+6m=46), (m=3).
Step 2
Why this answer is correct
The correct answer is A. (3). \(a_2=8+2m\) and \(a_4=20+4m\). From (28+6m=46), (m=3).
Step 3
Exam Tip
\(a_2=8+2m\) और \(a_4=20+4m\) है। (28+6m=46) से (m=3) मिलता है।
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श्रेणी \(3,13,33,63,103,\ldots\) का (n)वाँ पद क्या है?
What is the (n)th term of the sequence \(3,13,33,63,103,\ldots\)?
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A \(4n^2-2n+1\)
B \(5n^2-4n+2\)
C \(3n^2+5n-5\)
D \(5n^2-5n+3\)
Explanation opens after your attempt
Correct Answer
D. \(5n^2-5n+3\)
Step 1
Concept
The second difference is (10), so the coefficient of \(n^2\) is (5). The correct formula is \(5n^2-5n+3\).
Step 2
Why this answer is correct
The correct answer is D. \(5n^2-5n+3\). The second difference is (10), so the coefficient of \(n^2\) is (5). The correct formula is \(5n^2-5n+3\).
Step 3
Exam Tip
दूसरा अंतर (10) है इसलिए \(n^2\) का गुणांक (5) होगा। सही सूत्र \(5n^2-5n+3\) है।
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यदि (a_n=n(n+4)) है तो (117) कौन सा पद है?
If (a_n=n(n+4)), which term is (117)?
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A (8)वाँ / (8)th
B (9)वाँ / (9)th
C (10)वाँ / (10)th
D (11)वाँ / (11)th
Explanation opens after your attempt
Correct Answer
B. (9)वाँ / (9)th
Step 1
Concept
Putting (n=9) in (n(n+4)=117) gives \(9\cdot13=117\). Checking options is simple here.
Step 2
Why this answer is correct
The correct answer is B. (9)वाँ / (9)th. Putting (n=9) in (n(n+4)=117) gives \(9\cdot13=117\). Checking options is simple here.
Step 3
Exam Tip
(n(n+4)=117) में (n=9) रखने पर \(9\cdot13=117\) मिलता है। विकल्पों से जांचना यहां सरल है।
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यदि (a_n=4n+(-1)^{n+1}) है तो \(a_8\) का मान क्या होगा?
If (a_n=4n+(-1)^{n+1}), what will be the value of \(a_8\)?
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A (29)
B (30)
C (31)
D (33)
Explanation opens after your attempt
Step 1
Concept
(a_8=32+(-1)9 =31). Check the parity of the exponent in ((-1)^{n+1}).
Step 2
Why this answer is correct
The correct answer is C. (31). (a_8=32+(-1)9 =31). Check the parity of the exponent in ((-1)^{n+1}).
Step 3
Exam Tip
(a_8=32+(-1)9 =31) है। ((-1)^{n+1}) में घात की विषमता देखें।
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श्रेणी \(\frac{2}{9},\frac{5}{16},\frac{8}{23},\frac{11}{30},\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(\frac{2}{9},\frac{5}{16},\frac{8}{23},\frac{11}{30},\ldots\)?
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A \(\frac{3n-1}{7n+2}\)
B \(\frac{3n+1}{7n+1}\)
C \(\frac{2n}{7n+2}\)
D \(\frac{3n-1}{7n+3}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{3n-1}{7n+2}\)
Step 1
Concept
The numerator is (3n-1), and the denominator is (7n+2). Make separate arithmetic rules.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{3n-1}{7n+2}\). The numerator is (3n-1), and the denominator is (7n+2). Make separate arithmetic rules.
Step 3
Exam Tip
अंश (3n-1) और हर (7n+2) के रूप में है। अलग-अलग समांतर नियम बनाएं।
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यदि \(a_n=2n^3-n\) है तो \(a_4-a_2\) का मान क्या है?
If \(a_n=2n^3-n\), what is the value of \(a_4-a_2\)?
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A (104)
B (106)
C (108)
D (110)
Explanation opens after your attempt
Step 1
Concept
\(a_4=124\) and \(a_2=14\), so the difference is (110). Recheck calculations in cubic terms.
Step 2
Why this answer is correct
The correct answer is D. (110). \(a_4=124\) and \(a_2=14\), so the difference is (110). Recheck calculations in cubic terms.
Step 3
Exam Tip
\(a_4=124\) और \(a_2=14\) है इसलिए अंतर (110) है। घन वाले पदों में गणना दोबारा जांचें।
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श्रेणी \(5,18,43,80,129,\ldots\) का (n)वाँ पद क्या है?
What is the (n)th term of the sequence \(5,18,43,80,129,\ldots\)?
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A \(5n^2-4n+4\)
B \(6n^2-5n+4\)
C \(6n^2-4n+3\)
D \(4n^2+7n-6\)
Explanation opens after your attempt
Correct Answer
B. \(6n^2-5n+4\)
Step 1
Concept
The second difference is (12), so the coefficient of \(n^2\) is (6). Checking gives \(6n^2-5n+4\).
Step 2
Why this answer is correct
The correct answer is B. \(6n^2-5n+4\). The second difference is (12), so the coefficient of \(n^2\) is (6). Checking gives \(6n^2-5n+4\).
Step 3
Exam Tip
दूसरा अंतर (12) है इसलिए \(n^2\) का गुणांक (6) होगा। जांचने पर \(6n^2-5n+4\) सही है।
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यदि \(a_n=3n^2-5n+7\) है तो \(a_{n+1}-a_n\) क्या होगा?
If \(a_n=3n^2-5n+7\), what is \(a_{n+1}-a_n\)?
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A (6n-4)
B (6n)
C (6n-2)
D (3n-2)
Explanation opens after your attempt
Step 1
Concept
Expanding \(a_{n+1}\) and subtracting gives (6n-2). Pay attention to the sign of the negative term.
Step 2
Why this answer is correct
The correct answer is C. (6n-2). Expanding \(a_{n+1}\) and subtracting gives (6n-2). Pay attention to the sign of the negative term.
Step 3
Exam Tip
\(a_{n+1}\) का विस्तार करके घटाने पर (6n-2) मिलता है। ऋणात्मक पद का चिह्न ध्यान रखें।
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यदि (a_n=\frac{n(n+1)}{2}+3) है तो \(a_{10}\) क्या होगा?
If (a_n=\frac{n(n+1)}{2}+3), what will be \(a_{10}\)?
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A (58)
B (55)
C (60)
D (62)
Explanation opens after your attempt
Step 1
Concept
\(\frac{10\cdot11}{2}=55\) and (55+3=58). Do not forget the constant addition after the triangular number.
Step 2
Why this answer is correct
The correct answer is A. (58). \(\frac{10\cdot11}{2}=55\) and (55+3=58). Do not forget the constant addition after the triangular number.
Step 3
Exam Tip
\(\frac{10\cdot11}{2}=55\) और (55+3=58) है। त्रिभुज संख्या के बाद स्थिर जोड़ न भूलें।
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श्रेणी \(12,20,30,42,56,\ldots\) का (n)वाँ पद कौन सा है?
Which is the (n)th term of the sequence \(12,20,30,42,56,\ldots\)?
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A \(n^2+4n+7\)
B \(2n^2+4n+6\)
C \(n^2+6n+5\)
D \(n^2+5n+6\)
Explanation opens after your attempt
Correct Answer
D. \(n^2+5n+6\)
Step 1
Concept
The terms are like ((n+2)(n+3)). Therefore the formula is \(n^2+5n+6\).
Step 2
Why this answer is correct
The correct answer is D. \(n^2+5n+6\). The terms are like ((n+2)(n+3)). Therefore the formula is \(n^2+5n+6\).
Step 3
Exam Tip
पद ((n+2)(n+3)) जैसे हैं। इसलिए सूत्र \(n^2+5n+6\) बनता है।
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यदि \(a_n=8n-17\) है तो पहला धनात्मक पद कौन सा होगा?
If \(a_n=8n-17\), which will be the first positive term?
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A (2)वाँ पद / (2)nd term
B (3)वाँ पद / (3)rd term
C (4)वाँ पद / (4)th term
D (5)वाँ पद / (5)th term
Explanation opens after your attempt
Correct Answer
B. (3)वाँ पद / (3)rd term
Step 1
Concept
From (8n-17>0), we get \(n>\frac{17}{8}\). The first natural value is (3).
Step 2
Why this answer is correct
The correct answer is B. (3)वाँ पद / (3)rd term. From (8n-17>0), we get \(n>\frac{17}{8}\). The first natural value is (3).
Step 3
Exam Tip
(8n-17>0) से \(n>\frac{17}{8}\) मिलता है। पहला प्राकृतिक मान (3) है।
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यदि \(a_n=\frac{3n-2}{2n+1}\) है तो \(a_7\) का मान क्या है?
If \(a_n=\frac{3n-2}{2n+1}\), what is the value of \(a_7\)?
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A \(\frac{17}{15}\)
B \(\frac{18}{15}\)
C \(\frac{19}{15}\)
D \(\frac{20}{15}\)
Explanation opens after your attempt
Correct Answer
C. \(\frac{19}{15}\)
Step 1
Concept
Putting (n=7) gives \(\frac{21-2}{15}=\frac{19}{15}\). Simplify numerator and denominator separately.
Step 2
Why this answer is correct
The correct answer is C. \(\frac{19}{15}\). Putting (n=7) gives \(\frac{21-2}{15}=\frac{19}{15}\). Simplify numerator and denominator separately.
Step 3
Exam Tip
(n=7) रखने पर \(\frac{21-2}{15}=\frac{19}{15}\) मिलता है। अंश और हर को अलग-अलग सरल करें।
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श्रेणी \(4,-7,10,-13,16,\ldots\) का (n)वाँ पद क्या है?
What is the (n)th term of the sequence \(4,-7,10,-13,16,\ldots\)?
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A ((-1)^{n+1}(3n+1))
B ((-1)^n(3n+1))
C (3n+1)
D ((-1)^{n+1}(2n+2))
Explanation opens after your attempt
Correct Answer
A. ((-1)^{n+1}(3n+1))
Step 1
Concept
The magnitudes are (3n+1), and signs alternate. For a positive first term, ((-1)^{n+1}) is correct.
Step 2
Why this answer is correct
The correct answer is A. ((-1)^{n+1}(3n+1)). The magnitudes are (3n+1), and signs alternate. For a positive first term, ((-1)^{n+1}) is correct.
Step 3
Exam Tip
मान (3n+1) हैं और चिह्न बारी-बारी से बदलता है। धनात्मक पहले पद के लिए ((-1)^{n+1}) सही है।
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यदि \(a_n=an^2+bn+1\), \(a_1=6\) और \(a_2=17\) है तो \(a_5\) क्या होगा?
If \(a_n=an^2+bn+1\), \(a_1=6\), and \(a_2=17\), what will be \(a_5\)?
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A (76)
B (80)
C (84)
D (86)
Explanation opens after your attempt
Step 1
Concept
From (a+b=5) and (2a+b=8), we get (a=3), (b=2). Therefore \(a_5=86\).
Step 2
Why this answer is correct
The correct answer is D. (86). From (a+b=5) and (2a+b=8), we get (a=3), (b=2). Therefore \(a_5=86\).
Step 3
Exam Tip
(a+b=5) और (2a+b=8) से (a=3), (b=2) मिलता है। इसलिए \(a_5=86\) है।
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यदि \(a_n=2n^2+7n-4\) है तो \(a_8-a_3\) का मान क्या होगा?
If \(a_n=2n^2+7n-4\), what will be the value of \(a_8-a_3\)?
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A (145)
B (150)
C (155)
D (160)
Explanation opens after your attempt
Step 1
Concept
\(a_8=180\) and \(a_3=25\), so the difference is (155). In such questions, find both terms separately and subtract.
Step 2
Why this answer is correct
The correct answer is C. (155). \(a_8=180\) and \(a_3=25\), so the difference is (155). In such questions, find both terms separately and subtract.
Step 3
Exam Tip
\(a_8=180\) और \(a_3=25\) है इसलिए अंतर (155) है। ऐसे प्रश्नों में दोनों पद अलग-अलग निकालकर घटाएं।
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