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Medium · Level 12 · relations,symmetric relation,pair checking,class 12View options
(R) is symmetric
(R) is not symmetric
(R) is wrong because ((2,2)) is required
(R) is empty only
Medium · Level 12 · relations,symmetric relation,definition,class 12View options
((b,a)\in R)
((a,a)\in R)
((b,b)\in R)
((a+b,a-b)\in R)
Medium · Level 12 · relations,symmetric relation,condition comparison,class 12View options
(a=b+1)
(a+b=8)
(a^2+b^2=25)
(|a-b|=3)
Medium · Level 12 · relations,symmetric relation,prime numbers,class 12View options
Yes
No
Only for ((2,3))
Only for diagonal pairs
Medium · Level 12 · relations,symmetric relation,same parity,class 12View options
Symmetric
Not symmetric
Has only two pairs
Only on odd numbers
Medium · Level 12 · relations,symmetric relation,arrow diagram,class 12View options
Symmetry
Reflexivity
Transitivity
One-one property
Medium · Level 12 · relations,symmetric relation,missing pair,class 12View options
( (1,3) )
( (3,3) )
( (1,1) )
( (2,3) )
Medium · Level 12 · relations,symmetric relation,product parity,class 12View options
(R) is symmetric
(R) is not symmetric
(R) has no pairs
(R) contains only ((1,1))
Medium · Level 12 · relations,symmetric relation,algebraic condition,class 12View options
(R) is symmetric
(R) is not symmetric
(R) contains only ((1,1))
Reverse pairs never occur in (R)
Medium · Level 12 · relations,symmetric relation,algebra,class 12View options
Symmetric
Not symmetric
Empty only
Contains only ((1,4))
Medium · Level 12 · relations,symmetric relation,divisible difference,class 12View options
Yes
No
Only when (a<b)
Only when (a+b=2)
Medium · Level 12 · relations,symmetric relation,completion,class 12View options
( (3,1) )
( (1,1) )
( (2,2) )
( (3,3) )
Medium · Level 12 · relations,symmetric relation,multiple condition,class 12View options
(R) is symmetric because (a+b=b+a)
(R) is not symmetric because (5) is odd
(R) is symmetric only when (a=b)
(R) cannot have any pair
Medium · Level 12 · relations,symmetric relation,inverse test,class 12View options
When (R) is symmetric
When (R) is only a function
When (R) has no diagonal pair
When (R) is only on one element
Medium · Level 12 · relations,symmetric relation,sum pair,class 12View options
( (4,3) )
( (3,3) )
( (4,4) )
( (1,2) )
Medium · Level 12 · relations,symmetric relation,matrix,class 12View options
Yes
No
Only reflexive
Only empty
Medium · Level 12 · relations,symmetric relation,matrix counterexample,class 12View options
The relation is not symmetric
The relation is symmetric
The relation is empty
The relation is universal
Medium · Level 12 · relations,symmetric relation,diagonal relation,class 12View options
(R) is symmetric
(R) is never symmetric
(R) cannot have reverse pairs
(R) can only be universal
Medium · Level 12 · relations,symmetric relation,simplification,class 12View options
(R) is symmetric
(R) is not symmetric
(R) is empty only
(R) is universal
Medium · Level 12 · relations,symmetric relation,diagonal condition,class 12View options
(R) is symmetric
(R) is not symmetric
(R) contains only ((1,4))
(R) has no diagonal pair
Question 1MediumLevel 12
On (A={1,2,3}), (R={(1,1),(1,2),(2,1),(3,1),(1,3)}). Which option is correct for (R)?
Correct answer: A
Step 1: Check the reverse of every off-diagonal pair. Step 2: ((1,2)) has ((2,1)), and ((3,1)) has ((1,3)). The pair ((1,1)) is its own reverse. Step 3: ((2,2)) and ((3,3)) are not compulsory for symmetry.
If (R) is a symmetric relation and ((a,b)\in R), which statement is always true?
Correct answer: A
Step 1: The definition of symmetry is directly about the reverse ordered pair. Step 2: If ((a,b)\in R), then ((b,a)\in R) must be true. Step 3: Diagonal pairs are related to reflexivity, not necessarily to symmetry.
Which condition does not form a symmetric relation?
Correct answer: A
Step 1: (a=b+1) is a directional condition. Step 2: ((2,1)) satisfies it, but ((1,2)) does not. The other conditions remain the same after swapping (a) and (b). Step 3: Be cautious when the roles of (a) and (b) are not balanced.
On (A={1,2,3,4,5}), (R={(a,b):a\text{ and }b\text{ are both prime}}). Is (R) symmetric?
Correct answer: A
Step 1: The condition says both numbers are prime; it does not depend on direction. Step 2: If (a) and (b) are both prime, then (b) and (a) are also both prime. Step 3: Conditions where both variables have the same role usually preserve symmetry.
On (A={1,2,3,4}), (R={(a,b):a\text{ and }b\text{ have the same parity}}). Choose the correct statement about (R).
Correct answer: A
Step 1: Having the same parity is a two-way condition. Step 2: If (a) and (b) are both even or both odd, then (b) and (a) are also the same way. Step 3: Conditions based on belonging to the same class give symmetric relations.
If the arrow diagram of a relation shows a reverse arrow for every arrow, which property does the relation show?
Correct answer: A
Step 1: An arrow from (a) to (b) represents ((a,b)). Step 2: A reverse arrow for every arrow means ((b,a)) is also present, which is symmetry. Step 3: In diagram-based questions, observe arrow directions carefully.
On (A={1,2,3}), (R={(1,2),(2,1),(2,2),(3,1)}). Which pair must be added to make (R) symmetric?
Correct answer: A
Step 1: ((1,2)) and ((2,1)) are already balanced. Step 2: ((3,1)) is present, but its reverse ((1,3)) is missing. ((2,2)) is its own reverse. Step 3: Add only missing reverse pairs, not unnecessary diagonal pairs.
On (A={1,2,3,4}), (R={(a,b):ab\text{ is even}}). Which statement is correct about (R)?
Correct answer: A
Step 1: (ab) and (ba) are equal. Step 2: If (ab) is even, then (ba) is also even, so the reverse pair also belongs to the relation. Step 3: Multiplication is commutative, so product-based conditions often preserve symmetry.
On (A={1,2,3,4}), (R={(a,b):a+b=ab}). Choose the correct statement for (R).
Correct answer: A
Step 1: Swapping (a) and (b) in (a+b=ab) gives (b+a=ba). Step 2: Both addition and multiplication are commutative, so the condition remains the same. Step 3: If the full condition is unchanged after swapping, the relation is symmetric.
On (A={1,2,3,4}), (R={(a,b):a^2-b^2=0}). Which option is correct about (R)?
Correct answer: A
Step 1: (a^2-b^2=0) means (a^2=b^2). Step 2: If (a^2=b^2), then (b^2=a^2) is also true, so the reverse pair also belongs to the relation. Step 3: Simplifying the condition helps in exam questions.
On (A={1,2,3,4,5}), (R={(a,b):\text{the difference of }a\text{ and }b\text{ is divisible by }2}). Is (R) symmetric?
Correct answer: A
Step 1: The difference being divisible by (2) means (a-b) is even. Step 2: If (a-b) is even, then (b-a) is also even. Step 3: Difference conditions with zero remainder remain valid after reversing the pair.
On (A={1,2,3}), (R={(1,2),(2,1),(2,3),(3,2),(1,3)}). Which pair should be added to make (R) symmetric?
Correct answer: A
Step 1: ((1,2)) and ((2,1)) are both present, so they are fine. Step 2: ((2,3)) and ((3,2)) are also both present. Only the reverse of ((1,3)), which is ((3,1)), is missing. Step 3: Check off-diagonal pairs in reverse-pair groups.
If (R={(a,b):a+b\text{ is a multiple of }5}), which statement is correct based on symmetry?
Correct answer: A
Step 1: If (a+b) is a multiple of (5), then (b+a) gives the same sum. Step 2: Hence ((b,a)) belongs to the relation whenever ((a,b)) does. Step 3: For sum-multiple conditions, whether the modulus is even or odd does not affect symmetry.
In which option are a relation (R) and its inverse (R^{-1}) equal?
Correct answer: A
Step 1: In (R^{-1}), all ordered pairs are reversed. Step 2: (R=R^{-1}) exactly when every reverse pair is already in (R), which is symmetry. Step 3: (R=R^{-1}) is a very useful test for symmetry.
On (A={1,2,3,4}), (R={(a,b):a+b=7}). If ((3,4)\in R), which pair also belongs to (R) due to symmetry?
Correct answer: A
Step 1: The reverse of ((3,4)) is ((4,3)). Step 2: (3+4=7) and (4+3=7), so the reverse pair also satisfies the relation. Step 3: In sum conditions, reverse pairs can be checked quickly.
A relation on (A={1,2,3}) has the matrix (\begin{bmatrix}1&0&1\0&1&0\1&0&0\end{bmatrix}). Is the relation symmetric?
Correct answer: A
Step 1: For a relation matrix to represent a symmetric relation, entries across the main diagonal must match. Step 2: Here (m_{13}=1) and (m_{31}=1), and the other opposite entries also match. Step 3: A relation is symmetric when its matrix equals its transpose.
A relation on (A={1,2,3}) has the matrix (\begin{bmatrix}1&1&0\0&1&1\0&1&1\end{bmatrix}). Choose the correct statement.
Correct answer: A
Step 1: For symmetry in a matrix, we need (m_{ij}=m_{ji}). Step 2: Here (m_{12}=1), but (m_{21}=0), so a reverse pair is missing. Step 3: In matrix questions, compare entries across the main diagonal.
If a relation (R) contains only diagonal pairs of the form ((a,a)), which statement about (R) is correct?
Correct answer: A
Step 1: The reverse of a diagonal pair ((a,a)) is the same pair ((a,a)). Step 2: So the symmetry condition is automatically satisfied for every such pair. Step 3: Any relation containing only diagonal pairs is symmetric.
On (A={1,2,3,4}), (R={(a,b):a+b=2a}). Which statement is correct for (R)?
Correct answer: A
Step 1: From (a+b=2a), we get (b=a). Step 2: So the relation contains only diagonal pairs ((a,a)), and each is its own reverse. Step 3: Simplify the condition first, then check symmetry.
On (A={1,2,3,4}), (R={(a,b):a+b=2b}). Choose the correct option about (R).
Correct answer: A
Step 1: From (a+b=2b), we get (a=b). Step 2: Thus (R) contains only diagonal pairs such as ((1,1),(2,2),(3,3),(4,4)). Each is its own reverse. Step 3: Sometimes a condition that looks different may still define only a diagonal relation.
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