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Medium · Level 10 · symmetric not reflexive,property comparison,mcqView options
({(1,2),(2,1)})
({(1,1),(2,2),(3,3)})
({(1,2)})
({(1,1),(1,2),(2,3)})
Medium · Level 10 · not symmetric,diagonal pairs,common mistakeView options
({(1,1),(2,2),(1,3)})
({(1,2),(2,1)})
({(3,3)})
({(1,1),(2,2)})
Medium · Level 10 · relation matrix,symmetric matrix,main diagonalView options
Symmetric
Not symmetric
Empty
Not universal but asymmetric
Medium · Level 10 · relation matrix,not symmetric,reverse entryView options
(R) is not symmetric
(R) is definitely symmetric
(R) is definitely empty
(R) is definitely the identity relation
Medium · Level 10 · universal relation,symmetric relation,cartesian productView options
Because with every possible ((a,b)), ((b,a)) is also present
Because it has no pair
Because it has only ((1,1))
Because it has only increasing order pairs
Medium · Level 10 · empty relation,symmetric relation,vacuous truthView options
Because there is no pair that can violate the condition
Because it contains all reverse pairs
Because it contains only diagonal pairs
Because it is equal to (A\times A)
Medium · Level 10 · congruence modulo,symmetric relation,parityView options
Symmetric
Not symmetric
Only empty
Having only one pair
Medium · Level 10 · modulo relation,symmetric relation,congruenceView options
(R) is symmetric
(R) is not symmetric
(R) contains only ((1,1))
(R) has no reverse pair
Medium · Level 10 · not symmetric,successor relation,counterexampleView options
((2,1)\in R) but ((1,2)\notin R)
((1,1)\in R)
((3,3)\in R)
Every reverse pair is present
Medium · Level 10 · square equality,symmetric relation,integersView options
Symmetric
Not symmetric
Only empty
Having only one element
Medium · Level 10 · sum relation,counting pairs,symmetric relationView options
(4) pairs and symmetric
(2) pairs and not symmetric
(4) pairs and not symmetric
(0) pairs and empty
Medium · Level 10 · fixed difference,not symmetric,counterexampleView options
Not symmetric
Symmetric
Empty
Universal
Medium · Level 10 · absolute value,inequality,symmetric relationView options
(R) is symmetric
(R) is not symmetric
(R) has no diagonal pair
(R) has only one pair
Medium · Level 10 · symmetric relation,reverse pairs,logical conclusionView options
((5,2)) and ((6,4))
((2,2)) and ((4,4))
((5,5)) and ((6,6))
((2,4)) and ((5,6))
Medium · Level 10 · symmetric closure,minimum pairs,ordered pairsView options
(1)
(2)
(3)
(0)
Medium · Level 10 · inverse relation,symmetric relation,ordered pairsView options
(R)
(\varnothing)
(A\times A)
({(1,1),(2,2)})
Medium · Level 10 · inverse equality,symmetric relation,mcqView options
({(1,2),(2,1),(3,3)})
({(1,2),(2,3)})
({(1,3),(2,2)})
({(2,3),(3,3)})
Medium · Level 10 · gcd relation,symmetric relation,number theoryView options
Symmetric
Not symmetric
Only empty
Only reflexive
Medium · Level 10 · even numbers,symmetric relation,ordered pairsView options
(R) is symmetric
(R) is not symmetric
(R) is empty
(R) has only odd numbers
Medium · Level 10 · divisibility relation,not symmetric,counterexampleView options
((1,2)\in R) but ((2,1)\notin R)
((2,2)\notin R)
((4,4)\notin R)
Every pair has its reverse
Question 1MediumLevel 10
Which option gives a relation that is symmetric but not reflexive, where (A={1,2,3})?
Correct answer: A
Step 1: In option A, both ((1,2)) and ((2,1)) are present, so it is symmetric. Step 2: It does not contain all ((1,1),(2,2),(3,3)), so it is not reflexive. Step 3: In questions with two properties, check both conditions separately.
Which option gives a relation that is not symmetric but contains some diagonal pairs?
Correct answer: A
Step 1: Option A has diagonal pairs ((1,1)) and ((2,2)). Step 2: But the reverse of ((1,3)), which is ((3,1)), is missing, so it is not symmetric. Step 3: Having diagonal pairs does not automatically prove symmetry.
If the matrix of relation (R) is (\begin{pmatrix}1&0&1\0&1&0\1&0&1\end{pmatrix}), what type is (R)?
Correct answer: A
Step 1: Match the entries on both sides of the main diagonal. Step 2: Here (m_{13}=m_{31}=1), (m_{12}=m_{21}=0), and (m_{23}=m_{32}=0). Step 3: A matrix identical about the main diagonal represents a symmetric relation.
If the matrix of relation (R) has (m_{23}=1) and (m_{32}=0), what can be said about (R)?
Correct answer: A
Step 1: (m_{23}=1) means ((2,3)\in R). Step 2: (m_{32}=0) means ((3,2)\notin R). Step 3: If the reverse of one pair is missing, the relation is not symmetric.
If (A={1,2,3}) and (R=A\times A), why is (R) symmetric?
Correct answer: A
Step 1: (A\times A) contains all possible ordered pairs from (A). Step 2: Therefore the reverse ((b,a)) of any ((a,b)) is also present. Step 3: Remember that the universal relation is an important example of a symmetric relation.
Why is the empty relation (\varnothing) considered symmetric?
Correct answer: A
Step 1: The condition of symmetry is checked only for pairs that are present. Step 2: The empty relation has no pair, so there is no counterexample. Step 3: The empty relation is treated as symmetric automatically.
On (A={1,2,3,4,5}), what type is (R={(a,b):a\equiv b \pmod{2}})?
Correct answer: A
Step 1: (a\equiv b \pmod{2}) means (a) and (b) have the same parity. Step 2: If (a) has the same parity as (b), then (b) has the same parity as (a). Step 3: In similarity-type rules, check both directions naturally.
For (R={(a,b):a\equiv b \pmod{3}}) on (A={1,2,3,4,5}), which statement is correct?
Correct answer: A
Step 1: If (a\equiv b \pmod{3}), both leave the same remainder when divided by (3). Step 2: The same fact also gives (b\equiv a \pmod{3}). Step 3: Congruence rules are good examples of symmetry.
If (R={(a,b):a^2=b^2}) is defined on the set of integers, what type is (R)?
Correct answer: A
Step 1: If (a^2=b^2), then by reversing equality, (b^2=a^2) is also true. Step 2: Hence if ((a,b)) belongs to the relation, ((b,a)) also belongs. Step 3: In equality-based rules, swap the two sides to test symmetry.
On (A={1,2,3,4}), how many pairs are in (R={(a,b):a+b=5}), and what type is (R)?
Correct answer: A
Step 1: The pairs giving sum (5) are ((1,4),(2,3),(3,2),(4,1)). Step 2: The reverse of every pair is also in the list, so the relation is symmetric. Step 3: In counting questions, first list all pairs systematically.
On (A={1,2,3,4}), is (R={(a,b):a-b=2}) symmetric or not?
Correct answer: A
Step 1: ((3,1)\in R) because (3-1=2). Step 2: ((1,3)\notin R) because (1-3=-2), not (2). Step 3: In fixed difference rules, reversing may change the sign, so be careful.
On (A={1,2,3,4}), what is the correct conclusion for (R={(a,b):|a-b|\le 1})?
Correct answer: A
Step 1: (|a-b|) and (|b-a|) always have the same value. Step 2: Therefore, if (|a-b|\le 1), the reverse pair also satisfies the condition. Step 3: Absolute difference inequalities often lead to symmetric relations.
If (R) is symmetric and (R) contains ((2,5)) and ((4,6)), which group of pairs must be in (R)?
Correct answer: A
Step 1: In a symmetric relation, the reverse of every given pair must also exist. Step 2: The reverse of ((2,5)) is ((5,2)), and the reverse of ((4,6)) is ((6,4)). Step 3: For multiple pairs, reverse each pair separately.
If (R={(1,2),(2,1),(1,3),(3,1),(2,4)}), what is the minimum number of pairs needed to make it symmetric?
Correct answer: A
Step 1: The pair ((1,2)) and ((2,1)) is complete. Step 2: The pair ((1,3)) and ((3,1)) is also complete; only the reverse ((4,2)) of ((2,4)) is missing. Step 3: For minimum addition, count only missing reverse pairs.
If (R={(1,2),(2,1),(2,3),(3,2),(3,4),(4,3)}), what is (R^{-1})?
Correct answer: A
Step 1: In the inverse relation, all ordered pairs are reversed. Step 2: Here the reverse of every pair is already in the same relation. Step 3: When a relation is symmetric, its inverse is equal to itself.
Step 1: (R^{-1}=R) holds exactly when the relation is symmetric. Step 2: In option A, both ((1,2)) and ((2,1)) are present, and ((3,3)) is its own reverse. Step 3: Convert inverse questions into symmetry checks.
On (A={1,2,3,4}), what type is the relation (R={(a,b):\gcd(a,b)=1})?
Correct answer: A
Step 1: The greatest common divisor of two numbers does not change when the order changes. Step 2: If (\gcd(a,b)=1), then (\gcd(b,a)=1) also. Step 3: In number-property rules, swap the order and see whether the rule remains unchanged.
On (A={1,2,3,4,5,6}), which statement is correct for (R={(a,b):a\text{ and }b\text{ are both even}})?
Correct answer: A
Step 1: If (a) and (b) are both even, then after swapping, (b) and (a) are also both even. Step 2: Therefore, with ((a,b)), the reverse ((b,a)) also belongs to the relation. Step 3: When the same condition applies to both entries, check symmetry carefully.
On (A={1,2,3,4}), why is (R={(a,b):a\text{ divides }b}) not symmetric?
Correct answer: A
Step 1: (1) divides (2), so ((1,2)\in R). Step 2: (2) does not divide (1), so ((2,1)\notin R). Step 3: Divisibility generally does not remain the same after reversing the order.
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