Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 81-90 of 590 questions.
B. (114)
(5!=120) और (3!=6), इसलिए अंतर (114) है। घटाव करते समय क्रमगुणित का मान पहले निकालें। / (5!=120) and (3!=6), so the difference is (114). Find factorial values before subtracting.
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What is the value of \(\frac{3!+0!}{1!}\)?
B. (7)
(3!+0!=6+1=7) और (1!=1), इसलिए मान (7) है। (0!) और (1!) दोनों (1) होते हैं। / (3!+0!=6+1=7) and (1!=1), so the value is (7). Both (0!) and (1!) are (1).
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B. (4!)
\(4!=4\times3\times2\times1=24\)। छोटे क्रमगुणित मान याद रखना उपयोगी है। / \(4!=4\times3\times2\times1=24\). Remembering small factorial values is useful.
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How can (9!) be written using (10!)?
B. \(\frac{10!}{10}\)
\(10!=10\times9!\), इसलिए \(9!=\frac{10!}{10}\)। उलटा संबंध भी क्रमगुणित में काम आता है। / \(10!=10\times9!\), so \(9!=\frac{10!}{10}\). The reverse relation is also useful in factorials.
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What is the value of \(\frac{8!}{4!,4!}\)?
B. (70)
\(\frac{8!}{4!,4!}=\frac{8\times7\times6\times5}{4\times3\times2\times1}=70\)। क्रमगुणित काटकर संख्या छोटी करें। / \(\frac{8!}{4!,4!}=\frac{8\times7\times6\times5}{4\times3\times2\times1}=70\). Cancel factorials to make the numbers smaller.
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How many factors from (6) to (1) are present in (6!)?
B. (6)
\(6!=6\times5\times4\times3\times2\times1\), इसमें (6) गुणक हैं। (n!) में (n) गुणक होते हैं। / \(6!=6\times5\times4\times3\times2\times1\), which has (6) factors. (n!) has (n) factors.
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What is the value of \(\frac{7!}{5!}+1!\)?
B. (43)
\(\frac{7!}{5!}=7\times6=42\) और (1!=1), इसलिए कुल (43) है। पहले भाग को सरल करें। / \(\frac{7!}{5!}=7\times6=42\) and (1!=1), so the total is (43). Simplify the quotient first.
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What is the value of \(3!\times4!-4!\)?
C. (120)
\(3!\times4!-4!=6\times24-24=120\)। समान पद (4!) को अलग लेकर भी हल कर सकते हैं। / \(3!\times4!-4!=6\times24-24=120\). You may also factor out the common term (4!).
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If (x=5!) and (y=4!), what is the value of (x-y)?
A. (96)
(x=120) और (y=24), इसलिए (x-y=96)। चर को पहले उनके क्रमगुणित मान से बदलें। / (x=120) and (y=24), so (x-y=96). Replace variables by their factorial values first.
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What is the value of ((4-2)!)?
B. (2)
पहले (4-2=2), फिर (2!=2)। कोष्ठक को पहले हल करें। / First (4-2=2), then (2!=2). Solve the bracket first.
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