Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 101-110 of 590 questions.
B. (40320)
\(8!=8\times7!\) और (7!=5040), इसलिए मान (40320) है। बड़े क्रमगुणित को पिछले क्रमगुणित से निकालें। / \(8!=8\times7!\) and (7!=5040), so the value is (40320). Find a larger factorial using the previous factorial.
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What is the simplified value of \(\frac{12!}{11!}\)?
B. (12)
\(12!=12\times11!\), इसलिए भाग देने पर (12) बचता है। पास-पास के क्रमगुणित सीधे कटते हैं। / \(12!=12\times11!\), so division leaves (12). Consecutive factorials cancel directly.
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How will (6!) be written using (4!)?
C. \(6\times5\times4!\)
\(6!=6\times5\times4!\) होता है। क्रमगुणित को छोटे क्रमगुणित तक फैलाएं। / \(6!=6\times5\times4!\). Expand the factorial down to a smaller factorial.
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A. (722)
(2!=2) और (6!=720), इसलिए योग (722) है। जोड़ने से पहले हर क्रमगुणित का मान निकालें। / (2!=2) and (6!=720), so the sum is (722). Find each factorial value before adding.
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What is the value of \(\frac{10!}{7!}\)?
B. (720)
\(\frac{10!}{7!}=10\times9\times8=720\)। छोटे क्रमगुणित को काटकर केवल बचे गुणकों को गुणा करें। / \(\frac{10!}{7!}=10\times9\times8=720\). Cancel the smaller factorial and multiply only the remaining factors.
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If (n=5), what is the value of ((n-2)!)?
C. (6)
(n-2=3), इसलिए ((n-2)!=3!=6)। पहले कोष्ठक का मान निकालें। / (n-2=3), so ((n-2)!=3!=6). First evaluate the bracket.
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What is the value of \(\frac{9!}{6!,3!}\)?
B. (84)
\(\frac{9!}{6!,3!}=\frac{9\times8\times7}{6}=84\)। बड़े क्रमगुणित को छोटे तक तोड़ना आसान है। / \(\frac{9!}{6!,3!}=\frac{9\times8\times7}{6}=84\). Breaking the larger factorial down to the smaller one is easy.
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What is the value of \(5!\times0!\)?
C. (120)
(5!=120) और (0!=1), इसलिए गुणनफल (120) है। (0!) को (1) मानना जरूरी है। / (5!=120) and (0!=1), so the product is (120). It is necessary to take (0!) as (1).
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\(11\times10\times9!\) is equal to which of the following?
C. (11!)
\(11!=11\times10\times9!\), इसलिए दिया गया रूप (11!) है। क्रमगुणित विस्तार पहचानना मुख्य बात है। / \(11!=11\times10\times9!\), so the given form is (11!). Recognizing factorial expansion is the key point.
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B. (5041)
(7!=5040) और (0!=1), इसलिए योग (5041) है। (0!) वाले पद को न छोड़ें। / (7!=5040) and (0!=1), so the sum is (5041). Do not ignore the term with (0!).
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