Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 121-130 of 590 questions.
How many factors are present in (9!)?
C. (9)
(9!) में (9) से (1) तक कुल (9) गुणक होते हैं। (n!) में (n) गुणक होते हैं। / (9!) has (9) factors from (9) down to (1). (n!) has (n) factors.
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What is the value of \(5!\div4!+3!\)?
B. (11)
\(5!\div4!=5\) और (3!=6), इसलिए कुल (11) है। पहले भाग को सरल करें। / \(5!\div4!=5\) and (3!=6), so the total is (11). Simplify the division first.
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How can (13!) be written using (11!)?
C. \(13\times12\times11!\)
\(13!=13\times12\times11!\) होता है। बड़े क्रमगुणित को छोटे क्रमगुणित तक लिखें। / \(13!=13\times12\times11!\). Write the larger factorial down to the smaller factorial.
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What is the value of \(\frac{7!}{7\times6!}\)?
B. (1)
\(7!=7\times6!\), इसलिए अंश और हर समान हैं। समान अशून्य राशियों का भाग (1) होता है। / \(7!=7\times6!\), so numerator and denominator are the same. The quotient of equal non-zero quantities is (1).
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What is the value of (1!+4!+0!)?
C. (26)
(1!=1), (4!=24) और (0!=1), इसलिए योग (26) है। (0!) और (1!) दोनों (1) होते हैं। / (1!=1), (4!=24), and (0!=1), so the sum is (26). Both (0!) and (1!) are (1).
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What is the value of \(\frac{11!}{9!}\)?
B. (110)
\(\frac{11!}{9!}=11\times10=110\)। समान (9!) भाग को काट दें। / \(\frac{11!}{9!}=11\times10=110\). Cancel the common (9!) part.
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If (n!=5040), what is the value of (n)?
B. (7)
(7!=5040), इसलिए (n=7)। छोटे क्रमगुणित मान याद रखें। / (7!=5040), so (n=7). Remember small factorial values.
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What is the simplified form of (\frac{(n+2)!}{(n+1)!}+1)?
B. (n+3)
(\frac{(n+2)!}{(n+1)!}=n+2), इसलिए (1) जोड़ने पर (n+3) मिलता है। पहले भिन्न को सरल करें। / (\frac{(n+2)!}{(n+1)!}=n+2), so adding (1) gives (n+3). Simplify the fraction first.
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What is the value of \(2!\times3!\times4!\)?
C. (288)
(2!=2), (3!=6) और (4!=24), इसलिए गुणनफल (288) है। हर पद अलग निकालें। / (2!=2), (3!=6), and (4!=24), so the product is (288). Evaluate each term separately.
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What is the ratio of (6!) to (4!)?
A. (30:1)
\(\frac{6!}{4!}=6\times5=30\), इसलिए अनुपात (30:1) है। अनुपात में समान क्रमगुणित काटें। / \(\frac{6!}{4!}=6\times5=30\), so the ratio is (30:1). Cancel the common factorial in a ratio.
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