Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 131-140 of 590 questions.
B. (6!)
(6!=720) होता है। परीक्षा के लिए (1!) से (7!) तक के मान याद रखना उपयोगी है। / (6!=720). Remembering values from (1!) to (7!) is useful for exams.
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What is the value of ((6-3)!\times2!)?
B. (12)
((6-3)!=3!=6) और (2!=2), इसलिए गुणनफल (12) है। कोष्ठक पहले हल करें। / ((6-3)!=3!=6) and (2!=2), so the product is (12). Solve the bracket first.
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\(14\times13!\) is equal to which of the following?
C. (14!)
\(14!=14\times13!\), इसलिए दिया गया गुणनफल (14!) है। यह मूल क्रमगुणित पहचान है। / \(14!=14\times13!\), so the given product is (14!). This is a basic factorial identity.
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What is the value of \(\frac{5!}{1!,4!}\)?
B. (5)
\(\frac{5!}{1!,4!}=\frac{5\times4!}{1\times4!}=5\)। (1!) का मान (1) होता है। / \(\frac{5!}{1!,4!}=\frac{5\times4!}{1\times4!}=5\). The value of (1!) is (1).
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What is the value of \(4!\times2!-3!\)?
C. (42)
\(4!\times2!-3!=24\times2-6=42\)। क्रमगुणित मानों को पहले संख्याओं में बदलें। / \(4!\times2!-3!=24\times2-6=42\). Convert factorial values into numbers first.
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How can (8!) be written using (9!)?
A. \(\frac{9!}{9}\)
\(9!=9\times8!\), इसलिए \(8!=\frac{9!}{9}\)। बड़े क्रमगुणित से छोटा क्रमगुणित भी निकाला जा सकता है। / \(9!=9\times8!\), so \(8!=\frac{9!}{9}\). A smaller factorial can also be found from a larger factorial.
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What is the value of \(\frac{12!}{10!}\)?
C. (132)
\(\frac{12!}{10!}=12\times11=132\)। छोटे क्रमगुणित को काटने के बाद बचे गुणक गुणा करें। / \(\frac{12!}{10!}=12\times11=132\). After cancelling the smaller factorial, multiply the remaining factors.
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If (p=0!) and (q=1!), what is the value of (p+q)?
C. (2)
(0!=1) और (1!=1), इसलिए (p+q=2)। (0!) और (1!) के मान बराबर हैं। / (0!=1) and (1!=1), so (p+q=2). The values of (0!) and (1!) are equal.
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What is the difference between \(7!\div5!\) and (2!)?
B. (40)
\(7!\div5!=42\) और (2!=2), इसलिए अंतर (40) है। पहले दोनों भागों के मान निकालें। / \(7!\div5!=42\) and (2!=2), so the difference is (40). First find the values of both parts.
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What is the last factor in (5!)?
B. (1)
\(5!=5\times4\times3\times2\times1\), इसलिए अंतिम गुणक (1) है। क्रमगुणित हमेशा (1) तक जाता है। / \(5!=5\times4\times3\times2\times1\), so the last factor is (1). A factorial always goes down to (1).
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