Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 71-80 of 590 questions.
What is the value of \(\frac{4!+2!}{2!}\)?
C. (13)
\(\frac{4!+2!}{2!}=\frac{24+2}{2}=13\)। जोड़ वाले अंश को पहले पूरा करें। / \(\frac{4!+2!}{2!}=\frac{24+2}{2}=13\). Complete the addition in the numerator first.
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What is the value of \(5!\div3!\)?
C. (20)
\(5!\div3!=\frac{5!}{3!}=5\times4=20\)। भाग को भिन्न के रूप में लिखकर हल करें। / \(5!\div3!=\frac{5!}{3!}=5\times4=20\). Write division as a fraction to solve.
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If (a=3!) and (b=2!), what is the value of (a+b)?
C. (8)
(a=6) और (b=2), इसलिए (a+b=8)। चर वाले प्रश्नों में पहले मान निकालें। / (a=6) and (b=2), so (a+b=8). In variable questions, find the values first.
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What is the simplified value of \(\frac{9!}{6!}\)?
A. (504)
\(\frac{9!}{6!}=9\times8\times7=504\)। छोटे क्रमगुणित तक विस्तार करें और काटें। / \(\frac{9!}{6!}=9\times8\times7=504\). Expand down to the smaller factorial and cancel.
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B. (25)
(0!=1) और (4!=24), इसलिए योग (25) है। (0!) को (1) लेना याद रखें। / (0!=1) and (4!=24), so the sum is (25). Remember to take (0!) as (1).
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How can (10!) be written using (8!)?
B. \(10\times9\times8!\)
\(10!=10\times9\times8!\) होता है। बड़े क्रमगुणित को छोटे क्रमगुणित से जोड़कर लिखें। / \(10!=10\times9\times8!\). Write the larger factorial in terms of the smaller factorial.
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What is the simplified form of (\frac{(n+1)!}{(n-1)!})?
B. (n(n+1))
((n+1)!=(n+1)n(n-1)!), इसलिए शेष (n(n+1)) है। समान क्रमगुणित भाग काटें। / ((n+1)!=(n+1)n(n-1)!), so the remaining part is (n(n+1)). Cancel the common factorial part.
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What is the value of \(2!\times5!\)?
C. (240)
(2!=2) और (5!=120), इसलिए गुणनफल (240) है। पहले क्रमगुणित मान निकालें। / (2!=2) and (5!=120), so the product is (240). First find the factorial values.
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What is the value of \(\frac{6!}{4!}+0!\)?
C. (31)
\(\frac{6!}{4!}=6\times5=30\) और (0!=1), इसलिए कुल (31) है। (0!) को सही मान दें। / \(\frac{6!}{4!}=6\times5=30\) and (0!=1), so the total is (31). Use the correct value of (0!).
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What is the ratio of (4!) to (3!)?
A. (4:1)
\(\frac{4!}{3!}=4\), इसलिए अनुपात (4:1) है। अनुपात के लिए दोनों पदों को (3!) से काटें। / \(\frac{4!}{3!}=4\), so the ratio is (4:1). For the ratio, cancel both terms by (3!).
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