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What is the nature of the roots of the equation \(x^2-3x+2=0\)?

Answer and explanation

Correct answer: Real, rational and distinct

Here \(a=1\), \(b=-3\), and \(c=2\), so the discriminant is \(D=b^2-4ac=(-3)^2-4(1)(2)=1\). Since \(D>0\) and is a perfect square, the roots are real, rational, and distinct. In fact, \(x^2-3x+2=(x-1)(x-2)\), giving the roots \(1\) and \(2\). Exam tip: \(D>0\) indicates distinct roots, and if \(D\) is a perfect square, those roots are rational.

Related tags

Quadratic EquationsNature Of RootsDiscriminantRational RootsMathematicsClass 10 Mcq

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