यदि \(x^2+kx+16=0\) के मूल समान हैं तो \(k^2\) का मान क्या है?
If the roots of \(x^2+kx+16=0\) are equal, what is the value of \(k^2\)?
Explanation opens after your attempt
A. (64)
Concept
For equal roots (D=0), so \(k^2-64=0\). Therefore \(k^2=64\).
Why this answer is correct
The correct answer is A. (64). For equal roots (D=0), so \(k^2-64=0\). Therefore \(k^2=64\).
Exam Tip
समान मूलों के लिए (D=0) होता है इसलिए \(k^2-64=0\)। अतः \(k^2=64\) है।
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