यदि \(x^2+kx+16=0\) के मूल समान हैं तो \(k^2\) का मान क्या है?

If the roots of \(x^2+kx+16=0\) are equal, what is the value of \(k^2\)?

Explanation opens after your attempt
Correct Answer

A. (64)

Step 1

Concept

For equal roots (D=0), so \(k^2-64=0\). Therefore \(k^2=64\).

Step 2

Why this answer is correct

The correct answer is A. (64). For equal roots (D=0), so \(k^2-64=0\). Therefore \(k^2=64\).

Step 3

Exam Tip

समान मूलों के लिए (D=0) होता है इसलिए \(k^2-64=0\)। अतः \(k^2=64\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+kx+16=0\) के मूल समान हैं तो \(k^2\) का मान क्या है? / If the roots of \(x^2+kx+16=0\) are equal, what is the value of \(k^2\)?

Correct Answer: A. (64). Explanation: समान मूलों के लिए (D=0) होता है इसलिए \(k^2-64=0\)। अतः \(k^2=64\) है। / For equal roots (D=0), so \(k^2-64=0\). Therefore \(k^2=64\).

Which concept should I revise for this Mathematics MCQ?

For equal roots (D=0), so \(k^2-64=0\). Therefore \(k^2=64\).

What exam hint can help solve this Mathematics question?

समान मूलों के लिए (D=0) होता है इसलिए \(k^2-64=0\)। अतः \(k^2=64\) है।