If the discriminant \(D\) of the quadratic equation \(ax^2+bx+c=0\) is greater than zero, what will be the nature of its roots?

Correct answer: Two real and distinct roots

For a quadratic equation, the discriminant is \(D=b^2-4ac\). When \(D>0\), \(\sqrt{D}\) is positive and real, so the two signs in \(x=\frac{-b\pm\sqrt{D}}{2a}\) give two distinct real roots. Equal roots occur when \(D=0\), while no real roots occur when \(D<0\); therefore, options B and C are incorrect. In an exam, first check the sign of the discriminant to determine the nature of the roots.