समीकरण \(x^2+2x+k=0\) के वास्तविक मूल होने के लिए (k) के बारे में कौन सी शर्त सही है?

For \(x^2+2x+k=0\) to have real roots, which condition on (k) is correct?

Explanation opens after your attempt
Correct Answer

A. \(k\le1\)

Step 1

Concept

For real roots \(D\ge0\) is required. From \(4-4k\ge0\), we get \(k\le1\).

Step 2

Why this answer is correct

The correct answer is A. \(k\le1\). For real roots \(D\ge0\) is required. From \(4-4k\ge0\), we get \(k\le1\).

Step 3

Exam Tip

वास्तविक मूलों के लिए \(D\ge0\) चाहिए। \(4-4k\ge0\) से \(k\le1\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2+2x+k=0\) के वास्तविक मूल होने के लिए (k) के बारे में कौन सी शर्त सही है? / For \(x^2+2x+k=0\) to have real roots, which condition on (k) is correct?

Correct Answer: A. \(k\le1\). Explanation: वास्तविक मूलों के लिए \(D\ge0\) चाहिए। \(4-4k\ge0\) से \(k\le1\) मिलता है। / For real roots \(D\ge0\) is required. From \(4-4k\ge0\), we get \(k\le1\).

Which concept should I revise for this Mathematics MCQ?

For real roots \(D\ge0\) is required. From \(4-4k\ge0\), we get \(k\le1\).

What exam hint can help solve this Mathematics question?

वास्तविक मूलों के लिए \(D\ge0\) चाहिए। \(4-4k\ge0\) से \(k\le1\) मिलता है।