For which (q) will (3x^2+qx+12=0) have equal roots?
For equal roots, (D=0), so (q^2-144=0) and (q=\pm12). In exams, both signs of (b) may be possible.
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SubjectsMathematics
मूलों की प्रकृति
In Class 10 Mathematics, Nature of Roots explains how to determine the type and number of solutions of a quadratic equation. Students use the discriminant, b² − 4ac, to identify whether an equation has two distinct real roots, two equal real roots, or no real roots. The topic connects algebraic calculations with the graph of a quadratic function and helps learners interpret equations, compare cases, and solve related problems from the chapter Quadratic Equations.
TOPIC PRACTICE
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For equal roots, (D=0), so (q^2-144=0) and (q=\pm12). In exams, both signs of (b) may be possible.
View question detailsHere (D=(-11)^2-4\cdot6\cdot3=49), a positive perfect square. In exams, roots are rational in such cases.
View question detailsHere (D=(-4)^2-4\cdot3\cdot2=-8), so there are no real roots. In exams, negative (D) means no intersection on the real number line.
View question detailsFor a quadratic equation to have equal roots, its discriminant must be zero. Here, \(a=1\), \(b=k+2\), and \(c=9\), so \(D=(k+2)^2-4(1)(9)=0\). Therefore, \((k+2)^2=36\), giving \(k+2=\pm6\) and hence \(k=4\) or \(k=-8\). Option B results from reversing the signs incorrectly. Exam tip: For equal roots, begin by setting the discriminant \(D\) equal to zero.
View question detailsFor equal roots, (D=0), so (100-4t=0) gives (t=25). In exams, (b^2=4ac) is a quick sign of equal roots.
View question detailsHere (D=(-7)^2-4\cdot2\cdot6=1), so the roots are two distinct real roots. In exams, (D=1) is also a positive perfect square.
View question detailsFrom (D=0), ((4k)^2-4\cdot4\cdot k=0), that is (16k(k-1)=0). So (k=0) or (k=1), and (a=4\neq0).
View question detailsHere (D=(2\sqrt{3})^2-4\cdot1\cdot3=0), so the roots are equal and real. In exams, be careful while squaring a surd coefficient.
View question detailsHere (D=(2\sqrt{2})^2-4\cdot1\cdot1=4), so (D>0). In exams, (D=4) gives two distinct real roots.
View question detailsFor equal roots, the discriminant must be zero. Here, \(a=1\), \(b=-2(m+1)\), and \(c=16\). Thus, \(D=b^2-4ac=[-2(m+1)]^2-64=0\), giving \((m+1)^2=16\). Hence, \(m+1=\pm4\), so \(m=3\) or \(m=-5\). Exam tip: In questions involving equal roots of a quadratic equation, begin by using \(D=0\).
View question detailsFor two distinct real roots, (D>0), so (25-4r^2>0). Also (r\neq0) is needed because the equation must remain quadratic.
View question detailsFor no real roots, (D<0), so (4-4\lambda<0) gives (\lambda>1). In exams, keep strict inequality separate from equality.
View question detailsHere (D=20^2-4\cdot5\cdot20=0), so the roots are equal and real. In exams, removing a common factor does not change the nature.
View question detailsHere (D=(-3)^2-4\cdot10\cdot2=-71), so it has no real roots. In exams, small (b^2) and large (4ac) can make (D<0).
View question detailsFor real and distinct roots, (D>0), so (16-8n>0) gives (n<2). In exams, do not forget coefficient (a) in (4ac).
View question detailsFor equal roots, (D=0), so ((2s)^2-4s=0) gives (4s(s-1)=0). (s=0) does not make a quadratic, so (s=1).
View question details(D=-5) is negative, so there will be no real roots. In exams, (D<0) may also be linked with complex roots.
View question detailsHere (D=4^2-4\cdot1\cdot8=-16), so there are no real roots. In exams, (D<0) means no cut with the (x)-axis.
View question detailsHere (D=(-6)^2-4\cdot1\cdot9=0), so the graph touches the (x)-axis once. In exams, (D=0) indicates tangency.
View question detailsHere (D=(-5)^2-4\cdot1\cdot4=9), so there are two distinct real roots. In exams, (D>0) means two cuts with the (x)-axis.
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