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What will be the nature of roots of (x^2+2\sqrt{2}x+1=0)?द्विघात समीकरण (x^2+2\sqrt{2}x+1=0) के मूलों की प्रकृति क्या होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Two distinct real rootsदो भिन्न वास्तविक मूल
Here (D=(2\sqrt{2})^2-4\cdot1\cdot1=4), so (D>0). In exams, (D=4) gives two distinct real roots.यहां (D=(2\sqrt{2})^2-4\cdot1\cdot1=4), इसलिए (D>0)। परीक्षा में (D=4) होने पर दो भिन्न वास्तविक मूल होते हैं।
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