किस (r) के लिए \(rx^2-5x+r=0\) के दो भिन्न वास्तविक मूल होंगे?
For which (r) will \(rx^2-5x+r=0\) have two distinct real roots?
Explanation opens after your attempt
Correct Answer
A. \(r^2<\frac{25}{4}\) और \(r\neq0\)\(r^2<\frac{25}{4}\) and \(r\neq0\)
Concept
For two distinct real roots, (D>0), so \(25-4r^2>0\). Also \(r\neq0\) is needed because the equation must remain quadratic.
Why this answer is correct
The correct answer is A. \(r^2<\frac{25}{4}\) और \(r\neq0\) / \(r^2<\frac{25}{4}\) and \(r\neq0\). For two distinct real roots, (D>0), so \(25-4r^2>0\). Also \(r\neq0\) is needed because the equation must remain quadratic.
Exam Tip
दो भिन्न वास्तविक मूलों के लिए (D>0), इसलिए \(25-4r^2>0\)। साथ में \(r\neq0\) चाहिए क्योंकि समीकरण द्विघात होना चाहिए।
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