द्विघात समीकरण \(x^2+2\sqrt{3}x+3=0\) के मूलों की प्रकृति क्या है?
What is the nature of roots of \(x^2+2\sqrt{3}x+3=0\)?
Explanation opens after your attempt
Correct Answer
A. दो बराबर वास्तविक मूलTwo equal real roots
Concept
Here (D=\(2\sqrt{3}\)2-4\cdot1\cdot3=0), so the roots are equal and real. In exams, be careful while squaring a surd coefficient.
Why this answer is correct
The correct answer is A. दो बराबर वास्तविक मूल / Two equal real roots. Here (D=\(2\sqrt{3}\)2-4\cdot1\cdot3=0), so the roots are equal and real. In exams, be careful while squaring a surd coefficient.
Exam Tip
यहां (D=\(2\sqrt{3}\)2-4\cdot1\cdot3=0), इसलिए मूल बराबर वास्तविक हैं। परीक्षा में surd coefficient को square करते समय सावधानी रखें।
Login to save your score, XP, coins and progress.