What is the value of ((2^{-3}+2^{-2})^{-1})?
Inside, (2^{-3}+2^{-2}=\dfrac{1}{8}+\dfrac{1}{4}=\dfrac{3}{8}), so the power (-1) gives (\dfrac{8}{3}). In exams, simplify the bracket first.
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SubjectsMathematics
वास्तविक संख्याओं पर संक्रियाएँ और घातांक के नियम
In this Class 10 Mathematics topic from the Polynomials chapter, students strengthen their understanding of operations on real numbers and the laws of exponents. They learn to add, subtract, multiply and divide numerical expressions accurately, use exponent rules for products, quotients and powers, and simplify expressions involving positive, zero and negative exponents where appropriate. The topic builds fluency in working with polynomial terms, comparing equivalent forms, and checking calculations through properties such as commutativity, associativity and distributivity. Examples connect numerical rules with algebraic manipulation and related exercises.
TOPIC PRACTICE
Up to 20 questions from this page. Select your focus, then start.
Inside, (2^{-3}+2^{-2}=\dfrac{1}{8}+\dfrac{1}{4}=\dfrac{3}{8}), so the power (-1) gives (\dfrac{8}{3}). In exams, simplify the bracket first.
View question details(x^4-81=(x^2-9)(x^2+9)), so the simplified form is (x^2-9). In exams, treat (x^4) as ((x^2)^2) while factoring.
View question detailsAdding like terms gives (4x^2-x^2=3x^2), (-3x+7x=4x), and (6-9=-3). In exams, add like terms separately.
View question detailsChanging all signs in the second bracket gives (2y^3-y+5-5y^3-4y+8). In exams, change the sign of every term during subtraction.
View question detailsOn expansion, ((x+1)^3=x^3+3x^2+3x+1) and ((x-1)^3=x^3-3x^2+3x-1), so the difference is (6x^2+2). In exams, expand cubes carefully.
View question detailsUsing the laws of exponents, \(a^{2m+n}=a^{2m}\cdot a^n=(a^m)^2\cdot a^n\). Substituting the given values gives \(2^2\times 7=4\times 7=28\). Therefore, the correct answer is 28. In an exam, split a sum in the exponent into a product of powers; multiplying \(a^m\) and \(a^n\) directly would give 14, which corresponds to \(a^{m+n}\).
View question details((64)^{\frac{1}{3}}=4), ((x^6)^{\frac{1}{3}}=x^2), and ((y^{-3})^{\frac{1}{3}}=y^{-1}), so the answer is (\dfrac{4x^2}{y}). In exams, apply the exponent to each factor.
View question detailsBecause (\sqrt{a^4}=a^2) and (\sqrt{b^2}=b), the simplified form is (a^2b). In exams, note the positive condition.
View question detailsThe numerator difference is (6x^2y+2y^3=2y(3x^2+y^2)), so division gives (3x^2+y^2). In exams, take out the common factor.
View question details(9^2=3^4) and (27^{-1}=3^{-3}), so the value is (3^{-2+4-(-3)}=3^5=243). In exams, be careful while subtracting a negative exponent.
View question details(\dfrac{a^5}{a^k}=a^{5-k}), so (5-k=2) and (k=3). In exams, subtract exponents using the division law.
View question detailsThe numerator is ((2x)^3(3x^{-2})=8x^3\cdot 3x^{-2}=24x), and (\dfrac{24x}{12x^{-1}}=2x^2). In exams, simplify both coefficient and variable parts.
View question details(\sqrt{98}=7\sqrt{2}), (\sqrt{72}=6\sqrt{2}), and (\sqrt{50}=5\sqrt{2}), so the answer is (8\sqrt{2}). In exams, first write all surds in simplest form.
View question detailsMultiplying by (2+\sqrt{3}) makes the denominator (4-3=1). In exams, multiply both numerator and denominator by the conjugate.
View question details(4^{-1}-5^{-1}=\dfrac{1}{4}-\dfrac{1}{5}=\dfrac{1}{20}), so the whole value is (20). In exams, first convert negative powers into fractions.
View question detailsBecause (x^2+3x+2=(x+1)(x+2)), the simplified form is (x+2). In exams, factorise trinomials carefully.
View question details(125^{\frac{2}{3}}=25) and (25^{\frac{1}{2}}=5), so the value is (5). In exams, separate fractional exponents into root and power.
View question detailsSquaring both sides gives (n=(3\sqrt{7})^2=9\times 7=63). In exams, square both sides in a square root equation.
View question detailsThe numerator is (a^{-1}+b^{-1}=\dfrac{a+b}{ab}) and the denominator is ((ab)^{-1}=\dfrac{1}{ab}), so the answer is (a+b). In exams, make a common denominator.
View question details((2^5)^{\frac{2}{5}}=2^2=4) and ((3^3)^{\frac{1}{3}}=3), so the product is (12). In exams, apply the power of a power law.
View question detailsQUIZ COMPLETE