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If \(a^m=2\) and \(a^n=7\), what is the value of \(a^{2m+n}\)?

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Answer and explanation

Correct answer: 28

Using the laws of exponents, \(a^{2m+n}=a^{2m}\cdot a^n=(a^m)^2\cdot a^n\). Substituting the given values gives \(2^2\times 7=4\times 7=28\). Therefore, the correct answer is 28. In an exam, split a sum in the exponent into a product of powers; multiplying \(a^m\) and \(a^n\) directly would give 14, which corresponds to \(a^{m+n}\).

Related tags

PolynomialsLaws Of ExponentsReal NumbersPowersAlgebraic Reasoning

Frequently asked questions

What is the correct answer to this question?

28

Why is this the correct answer?

Using the laws of exponents, \(a^{2m+n}=a^{2m}\cdot a^n=(a^m)^2\cdot a^n\). Substituting the given values gives \(2^2\times 7=4\times 7=28\). Therefore, the correct answer is 28. In an exam, split a sum in the exponent into a product of powers; multiplying \(a^m\) and \(a^n\) directly would give 14, which corresponds to \(a^{m+n}\).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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