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If (a \neq 0) and (b \neq 0), what is the simplified form of (\dfrac{a^{-1}+b^{-1}}{(ab)^{-1}})?
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Answer and explanation
Correct answer: (,a+b,)
The numerator is (a^{-1}+b^{-1}=\dfrac{a+b}{ab}) and the denominator is ((ab)^{-1}=\dfrac{1}{ab}), so the answer is (a+b). In exams, make a common denominator.
Frequently asked questions
What is the correct answer to this question?
(,a+b,)
Why is this the correct answer?
The numerator is (a^{-1}+b^{-1}=\dfrac{a+b}{ab}) and the denominator is ((ab)^{-1}=\dfrac{1}{ab}), so the answer is (a+b). In exams, make a common denominator.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
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