0 reads0 ratings0 helpful
What is the value of (\dfrac{3^{-2}\times 9^2}{27^{-1}})?
Advertisement
Answer and explanation
Correct answer: (,243,)
(9^2=3^4) and (27^{-1}=3^{-3}), so the value is (3^{-2+4-(-3)}=3^5=243). In exams, be careful while subtracting a negative exponent.
Frequently asked questions
What is the correct answer to this question?
(,243,)
Why is this the correct answer?
(9^2=3^4) and (27^{-1}=3^{-3}), so the value is (3^{-2+4-(-3)}=3^5=243). In exams, be careful while subtracting a negative exponent.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement