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If (y \neq 0), what is the simplified form of ((64x^6y^{-3})^{\frac{1}{3}})?
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Answer and explanation
Correct answer: (,\dfrac{4x^2}{y},)
((64)^{\frac{1}{3}}=4), ((x^6)^{\frac{1}{3}}=x^2), and ((y^{-3})^{\frac{1}{3}}=y^{-1}), so the answer is (\dfrac{4x^2}{y}). In exams, apply the exponent to each factor.
Frequently asked questions
What is the correct answer to this question?
(,\dfrac{4x^2}{y},)
Why is this the correct answer?
((64)^{\frac{1}{3}}=4), ((x^6)^{\frac{1}{3}}=x^2), and ((y^{-3})^{\frac{1}{3}}=y^{-1}), so the answer is (\dfrac{4x^2}{y}). In exams, apply the exponent to each factor.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
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