remainder calculation se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
7 questions tagged with remainder calculation.
What is the remainder when (221) is divided by (18)?
B. (5)
\(18 \times 12=216\).
(221-216=5), so the remainder is (5).
Confirm that the remainder (5<18). चरण 1: \(18 \times 12=216\) है। चरण 2: (221-216=5), इसलिए शेषफल (5) है। चरण 3: शेषफल की पुष्टि करें कि (5<18) है।
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If (a=148) and (b=20), what is the remainder (r)?
A. (8)
\(20 \times 7=140\).
(148-140=8), so (r=8).
If an option gives a remainder equal to or greater than (20), reject it immediately. चरण 1: \(20 \times 7=140\)। चरण 2: (148-140=8), इसलिए (r=8)। चरण 3: यदि विकल्पों में (20) या उससे बड़ा शेषफल हो, तो उसे तुरंत गलत मानें।
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What is the remainder when (99) is divided by (14)?
A. (1)
\(14 \times 7=98\).
(99-98=1), so the remainder is (1).
The nearest smaller multiple helps find the remainder quickly. चरण 1: \(14 \times 7=98\) है। चरण 2: (99-98=1), इसलिए शेषफल (1) है। चरण 3: निकटतम छोटे गुणज से शेषफल जल्दी मिलता है।
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If (a=120) and (b=17), what is the correct value of (r)?
A. (1)
\(17 \times 7=119\).
(120-119=1), so the remainder is (1).
Since (1<17), this remainder is valid. चरण 1: \(17 \times 7=119\) है। चरण 2: (120-119=1), इसलिए शेषफल (1) होगा। चरण 3: (1<17), इसलिए यह शेषफल मान्य है।
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If (a=95) and (b=12), what is the value of (r) in (a=bq+r)?
A. (11)
\(12 \times 7=84\) and \(12 \times 8=96\).
The nearest smaller multiple of (12) is (84), so (95-84=11).
Since (11<12), remainder (11) is valid. चरण 1: \(12 \times 7=84\) और \(12 \times 8=96\) है। चरण 2: (95) से छोटा निकटतम गुणज (84) है, इसलिए (95-84=11)। चरण 3: (11<12), इसलिए शेषफल (11) मान्य है।
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What is the correct remainder when (58) is divided by (6)?
A. (4)
\(6 \times 9=54\).
(58-54=4), so the remainder is (4).
Since (4<6), the answer is valid. चरण 1: \(6 \times 9=54\) है। चरण 2: (58-54=4), इसलिए शेषफल (4) है। चरण 3: (4<6), इसलिए उत्तर मान्य है।
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What is the remainder when (100) is divided by (9)?
A. (1)
\(9 \times 11=99\).
(100-99=1), so the remainder is (1).
Using the nearest smaller multiple helps in quick calculation. चरण 1: \(9 \times 11=99\) है। चरण 2: (100-99=1), इसलिए शेषफल (1) होगा। चरण 3: निकटतम छोटे गुणज का उपयोग तेज गणना में मदद करता है।
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