Concept-wise Practice

powers-of-five MCQ Questions for Class 10

powers-of-five se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

5 questions tagged with powers-of-five.

Question 1/5 Medium Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

\(\frac{63}{175}\) को सरल करने के बाद दशमलव प्रसार कैसा होगा?

After simplifying \(\frac{63}{175}\), what type of decimal expansion will it have?

Explanation opens after your attempt
Correct Answer

A. समाप्तTerminating

Step 1

Concept

\(\frac{63}{175}=\frac{9}{25}\).

Step 2

Why this answer is correct

The reduced denominator is \(25=5^2\).

Step 3

Exam Tip

Since the denominator has only (5), the decimal terminates. चरण 1: \(\frac{63}{175}=\frac{9}{25}\) है। चरण 2: सरलतम हर \(25=5^2\) है। चरण 3: हर में केवल (5) होने से दशमलव समाप्त होगा।

Open Question Page
Ask Friends
Question 2/5 Medium Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

यदि सरलतम भिन्न का हर (3125) है, तो दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

If the denominator of a fraction in lowest form is (3125), after how many places will the decimal expansion terminate?

Explanation opens after your attempt
Correct Answer

C. (5) स्थान(5) places

Step 1

Concept

\(3125=5^5\).

Step 2

Why this answer is correct

The denominator has only (5), so the decimal terminates.

Step 3

Exam Tip

Since the exponent of (5) is (5), it terminates after (5) places. चरण 1: \(3125=5^5\) है। चरण 2: हर में केवल (5) है, इसलिए दशमलव समाप्त होगा। चरण 3: (5) की घात (5) होने से दशमलव (5) स्थानों पर समाप्त होगा।

Open Question Page
Ask Friends
Question 3/5 Medium Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

\(\frac{11}{6250}\) का दशमलव प्रसार कितने स्थानों पर समाप्त होगा?

After how many places will the decimal expansion of \(\frac{11}{6250}\) terminate?

Explanation opens after your attempt
Correct Answer

B. (5) स्थान(5) places

Step 1

Concept

\(6250=2\times5^5\).

Step 2

Why this answer is correct

The denominator contains only (2) and (5).

Step 3

Exam Tip

The larger exponent is (5), so the decimal terminates after (5) places. चरण 1: \(6250=2\times5^5\) है। चरण 2: हर में केवल (2) और (5) हैं। चरण 3: बड़ी घात (5) है, इसलिए दशमलव (5) स्थानों पर समाप्त होगा।

Open Question Page
Ask Friends
Question 4/5 Medium Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 20

\(\frac{7}{625}\) का दशमलव प्रसार कितने दशमलव स्थानों पर समाप्त होगा?

After how many decimal places will the decimal expansion of \(\frac{7}{625}\) terminate?

Explanation opens after your attempt
Correct Answer

C. (4) स्थान(4) places

Step 1

Concept

\(625=5^4\).

Step 2

Why this answer is correct

The denominator has only (5) with exponent (4).

Step 3

Exam Tip

Therefore the decimal terminates after (4) places. चरण 1: \(625=5^4\) है। चरण 2: हर में केवल (5) है और उसकी घात (4) है। चरण 3: इसलिए दशमलव (4) स्थानों पर समाप्त होगा।

Open Question Page
Ask Friends
Question 5/5 Easy Mathematics Real Numbers 7: Decimal expansion of rational numbers Class 10 Level 21

सरल भिन्न के हर \(5^3\) होने पर दशमलव प्रसार कितने स्थानों तक समाप्त होगा?

If the denominator of a fraction in lowest form is \(5^3\), after how many decimal places will the decimal expansion terminate?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

\(5^3=125\).

Step 2

Why this answer is correct

To make (125) into (1000), multiply by (8), so there are (3) decimal places.

Step 3

Exam Tip

Exam tip: A \(5^n\) denominator usually gives (n) decimal places. चरण 1: \(5^3=125\) है। चरण 2: (125) को (1000) बनाने के लिए (8) से गुणा करते हैं, इसलिए (3) दशमलव स्थान होंगे। चरण 3: परीक्षा सुझाव: \(5^n\) वाले हर में प्रायः (n) स्थान मिलते हैं।

Open Question Page
Ask Friends
Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.