असमानताओं \(x\leq 5\), \(y\leq 5\), \(x+y\geq 7\), \(x\geq 0\), \(y\geq 0\) का हल-क्षेत्र कौन सा बहुभुज है?
Explanation opens after your attempt
Correct Answer
A. त्रिभुज जिसके शीर्ष ((2,5)), ((5,2)), ((5,5)) हैंTriangle with vertices ((2,5)), ((5,2)), ((5,5))
Concept
Inside the square \(0\leq x\leq 5\), \(0\leq y\leq 5\), the part above (x+y=7) remains. Its vertices are ((2,5)), ((5,2)), and ((5,5)).
Why this answer is correct
The correct answer is A. त्रिभुज जिसके शीर्ष ((2,5)), ((5,2)), ((5,5)) हैं / Triangle with vertices ((2,5)), ((5,2)), ((5,5)). Inside the square \(0\leq x\leq 5\), \(0\leq y\leq 5\), the part above (x+y=7) remains. Its vertices are ((2,5)), ((5,2)), and ((5,5)).
Exam Tip
वर्ग \(0\leq x\leq 5\), \(0\leq y\leq 5\) में रेखा (x+y=7) के ऊपर का कोना बचता है। उसके शीर्ष ((2,5)), ((5,2)), ((5,5)) हैं।
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