Concept-wise Practice

mixed-expression MCQ Questions for Class 10

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Practice Questions

5 questions tagged with mixed-expression.

Question 1/5 Expert Mathematics Chapter 1: Real Numbers 1: Euclid’s Division Lemma Class 10 Level 3

यदि (a=24q+17) और (b=24p+22), तो (ab+a) को 24 से भाग देने पर शेषफल क्या होगा?

If (a=24q+17) and (b=24p+22), what is the remainder when (ab+a) is divided by 24?

Explanation opens after your attempt
Correct Answer

A. 5

Step 1

Concept

The remainders of (a) and (b) are 17 and 22.

Step 2

Why this answer is correct

The remainder of (ab+a) comes from \(17\times22+17=391\).

Step 3

Exam Tip

\(391=24\times16+7\), so the final remainder is 7. चरण 1: (a) और (b) के शेषफल 17 और 22 हैं। चरण 2: (ab+a) का शेषफल \(17\times22+17=391\) से मिलेगा। चरण 3: \(391=24\times16+7\), इसलिए अंतिम शेषफल 7 है।

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Question 2/5 Expert Mathematics Chapter 1: Real Numbers 1: Euclid’s Division Lemma Class 10 Level 2

यदि (a=20q+13) और (b=20p+18), तो (ab+a) को 20 से भाग देने पर शेषफल क्या होगा?

If (a=20q+13) and (b=20p+18), what is the remainder when (ab+a) is divided by 20?

Explanation opens after your attempt
Correct Answer

B. 7

Step 1

Concept

The remainders of (a) and (b) are 13 and 18.

Step 2

Why this answer is correct

The remainder of (ab+a) comes from \(13\times18+13=247\).

Step 3

Exam Tip

\(247=20\times12+7\), so the final remainder is 7. चरण 1: (a) और (b) के शेषफल 13 और 18 हैं। चरण 2: (ab+a) का शेषफल \(13\times18+13=247\) से मिलेगा। चरण 3: \(247=20\times12+7\), इसलिए अंतिम शेषफल 7 है।

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Question 3/5 Expert Mathematics Chapter 1: Real Numbers 1: Euclid’s Division Lemma Class 10 Level 1

यदि (a=16q+11) और (b=16p+14), तो (ab+a) को 16 से भाग देने पर शेषफल क्या होगा?

If (a=16q+11) and (b=16p+14), what is the remainder when (ab+a) is divided by 16?

Explanation opens after your attempt
Correct Answer

A. 5

Step 1

Concept

The remainders of (a) and (b) are 11 and 14.

Step 2

Why this answer is correct

The remainder of (ab+a) comes from \(11\times14+11=165\).

Step 3

Exam Tip

\(165=16\times10+5\), so the final remainder is 5. चरण 1: (a) और (b) के शेषफल 11 और 14 हैं। चरण 2: (ab+a) का शेषफल \(11\times14+11=165\) से मिलेगा। चरण 3: \(165=16\times10+5\), इसलिए अंतिम शेषफल 5 है।

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Question 4/5 Hard Mathematics Chapter 1: Real Numbers 1: Euclid’s Division Lemma Class 10 Level 3

यदि (a=14q+9) और (b=14p+6), तो (ab+a) को 14 से भाग देने पर शेषफल क्या होगा?

If (a=14q+9) and (b=14p+6), what is the remainder when (ab+a) is divided by 14?

Explanation opens after your attempt
Correct Answer

A. 7

Step 1

Concept

The remainders of (a) and (b) are 9 and 6.

Step 2

Why this answer is correct

The remainder of (ab+a) comes from \(9\times6+9=63\), and \(63=14\times4+7\).

Step 3

Exam Tip

In a mixed expression, handle the remainder of each term separately. चरण 1: (a) और (b) के शेषफल 9 और 6 हैं। चरण 2: (ab+a) का शेषफल \(9\times6+9=63\) से मिलेगा, और \(63=14\times4+7\)। चरण 3: मिश्रित व्यंजक में प्रत्येक पद का शेषफल अलग संभालें।

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Question 5/5 Hard Mathematics Chapter 1: Real Numbers 1: Euclid’s Division Lemma Class 10 Level 2

यदि (a=12q+8) और (b=12p+5), तो (ab+a) को 12 से भाग देने पर शेषफल क्या होगा?

If (a=12q+8) and (b=12p+5), what is the remainder when (ab+a) is divided by 12?

Explanation opens after your attempt
Correct Answer

A. 0

Step 1

Concept

The remainders of (a) and (b) are 8 and 5.

Step 2

Why this answer is correct

The remainder of (ab+a) comes from \(8\times5+8=48\), and 48 is divisible by 12.

Step 3

Exam Tip

In a mixed expression, find the remainder of each part separately. चरण 1: (a) और (b) के शेषफल 8 और 5 हैं। चरण 2: (ab+a) का शेषफल \(8\times5+8=48\) से मिलेगा, और 48, 12 से विभाज्य है। चरण 3: मिश्रित व्यंजक में हर पद का शेषफल अलग निकालें।

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