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exponent MCQ Questions for Class 10

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4 questions tagged with exponent.

Question 1/4 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 12

(224) के अभाज्य गुणनखंडन में (2) की घात कितनी है?

What is the exponent of (2) in the prime factorisation of (224)?

Explanation opens after your attempt
Correct Answer

B. 5

Step 1

Concept

Write (224) as \(32 \times 7\).

Step 2

Why this answer is correct

\(32=2^5\), so \(224=2^5 \times 7\).

Step 3

Exam Tip

Repeated division by the same prime helps find its exponent. चरण 1: (224) को \(32 \times 7\) लिखें। चरण 2: \(32=2^5\), इसलिए \(224=2^5 \times 7\)। चरण 3: किसी अभाज्य की घात जानने के लिए उसी अभाज्य से बार-बार भाग देना उपयोगी है।

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Question 2/4 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 11

(168) के अभाज्य गुणनखंडन में (2) की घात कितनी है?

What is the exponent of (2) in the prime factorisation of (168)?

Explanation opens after your attempt
Correct Answer

B. 3

Step 1

Concept

Write (168) as \(8 \times 21\).

Step 2

Why this answer is correct

\(8=2^3\) and \(21=3 \times 7\), so \(168=2^3 \times 3 \times 7\).

Step 3

Exam Tip

To find the required exponent, you do not need to calculate any extra value. चरण 1: (168) को \(8 \times 21\) के रूप में लिखें। चरण 2: \(8=2^3\) और \(21=3 \times 7\), इसलिए \(168=2^3 \times 3 \times 7\)। चरण 3: मांगी गई घात के लिए पूरी संख्या का मान निकालना जरूरी नहीं होता।

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Question 3/4 Medium Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 10

(96) के अभाज्य गुणनखंडन में (2) की घात कितनी है?

What is the exponent of (2) in the prime factorisation of (96)?

Explanation opens after your attempt
Correct Answer

B. 5

Step 1

Concept

Write (96) as \(32 \times 3\).

Step 2

Why this answer is correct

Since \(32=2^5\), \(96=2^5 \times 3\).

Step 3

Exam Tip

To find an exponent, divide repeatedly by that prime. चरण 1: (96) को \(32 \times 3\) लिख सकते हैं। चरण 2: \(32=2^5\), इसलिए \(96=2^5 \times 3\)। चरण 3: किसी अभाज्य की घात जानने के लिए उस अभाज्य से बार-बार भाग देना अच्छा तरीका है।

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Question 4/4 Expert Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9

(840) के अभाज्य गुणनखंडन में (7) की घात क्या है?

What is the exponent of (7) in the prime factorisation of (840)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

Write \(840=84 \times 10\).

Step 2

Why this answer is correct

Since \(84=2^2 \times 3 \times 7\) and \(10=2 \times 5\), \(840=2^3 \times 3 \times 5 \times 7\). The exponent of (7) is (1).

Step 3

Exam Tip

A prime appearing once has exponent (1). चरण 1: \(840=84 \times 10\) लिखें। चरण 2: \(84=2^2 \times 3 \times 7\) और \(10=2 \times 5\), इसलिए \(840=2^3 \times 3 \times 5 \times 7\)। (7) की घात (1) है। चरण 3: जो अभाज्य केवल एक बार आए, उसकी घात (1) होती है।

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