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evaluate-prime-factorisation MCQ Questions for Class 10

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5 questions tagged with evaluate-prime-factorisation.

Question 1/5 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^6\times3^2\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^6\times3^2\), what is the number?

Explanation opens after your attempt
Correct Answer

B. 576

Step 1

Concept

Calculate \(2^6=64\) and \(3^2=9\).

Step 2

Why this answer is correct

\(64\times9=576\).

Step 3

Exam Tip

In a form with powers, it is easier to evaluate powers first. चरण 1: \(2^6=64\) और \(3^2=9\) निकालें। चरण 2: \(64\times9=576\)। चरण 3: घात वाले रूप में पहले घातों का मान निकालना आसान होता है।

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Question 2/5 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^5\times3^2\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^5\times3^2\), what is the number?

Explanation opens after your attempt
Correct Answer

B. 288

Step 1

Concept

Calculate \(2^5=32\) and \(3^2=9\).

Step 2

Why this answer is correct

\(32\times9=288\).

Step 3

Exam Tip

In prime factorisation with powers, evaluate powers first. चरण 1: \(2^5=32\) और \(3^2=9\) निकालें। चरण 2: \(32\times9=288\)। चरण 3: घात वाले अभाज्य गुणनखंडन में पहले घातों का मान निकालें।

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Question 3/5 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^6\times3\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^6\times3\), what is the number?

Explanation opens after your attempt
Correct Answer

C. 192

Step 1

Concept

Find \(2^6=64\).

Step 2

Why this answer is correct

\(64\times3=192\), so the number is 192.

Step 3

Exam Tip

First evaluate the power, then multiply. चरण 1: \(2^6=64\) निकालें। चरण 2: \(64\times3=192\), इसलिए संख्या 192 है। चरण 3: पहले घात का मान निकालें और फिर गुणा करें।

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Question 4/5 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^5\times3\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^5\times3\), what is the number?

Explanation opens after your attempt
Correct Answer

B. 96

Step 1

Concept

Find \(2^5=32\).

Step 2

Why this answer is correct

\(32\times3=96\), so the number is 96.

Step 3

Exam Tip

First evaluate the power, then multiply. चरण 1: \(2^5=32\) निकालें। चरण 2: \(32\times3=96\), इसलिए संख्या 96 है। चरण 3: पहले घात का मान निकालें और फिर गुणा करें।

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Question 5/5 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

संख्या \(3^2\times5\) का मान क्या है?

What is the value of \(3^2\times5\)?

Explanation opens after your attempt
Correct Answer

B. 45

Step 1

Concept

First find \(3^2=9\).

Step 2

Why this answer is correct

\(9\times5=45\), so the number is 45.

Step 3

Exam Tip

In factorisation with powers, evaluate the power first. चरण 1: पहले \(3^2=9\) निकालें। चरण 2: \(9\times5=45\), इसलिए संख्या 45 है। चरण 3: घात वाले गुणनखंडन में पहले घात का मान निकालें।

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