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5 results found for "parameter_condition" in Class 10.

यदि समीकरण (x-2-4x+(m+4)=0) के वास्तविक मूल नहीं हैं तो (m) के लिए कौन सी शर्त सही है?

If (x-2-4x+(m+4)=0) has no real roots, which condition on (m) is correct?

Explanation opens after your attempt
Correct Answer

A. (m>0)

Step 1

Concept

For no real roots (D<0) is required. From (16-4(m+4)<0), we get (m>0).

Step 2

Why this answer is correct

The correct answer is A. (m>0). For no real roots (D<0) is required. From (16-4(m+4)<0), we get (m>0).

Step 3

Exam Tip

वास्तविक मूल नहीं होने के लिए (D<0) चाहिए। (16-4(m+4)<0) से (m>0) मिलता है।

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यदि समीकरण (x-2-2x+(m+1)=0) के वास्तविक मूल नहीं हैं तो (m) के लिए कौन सी शर्त सही है?

If (x-2-2x+(m+1)=0) has no real roots, which condition on (m) is correct?

Explanation opens after your attempt
Correct Answer

A. (m>0)

Step 1

Concept

For no real roots (D<0) is required. From (4-4(m+1)<0), we get (m>0).

Step 2

Why this answer is correct

The correct answer is A. (m>0). For no real roots (D<0) is required. From (4-4(m+1)<0), we get (m>0).

Step 3

Exam Tip

वास्तविक मूल नहीं होने के लिए (D<0) चाहिए। (4-4(m+1)<0) से (m>0) मिलता है।

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समीकरण \(x^2+6x+k=0\) के वास्तविक मूल होने के लिए (k) के बारे में कौन सी शर्त सही है?

For \(x^2+6x+k=0\) to have real roots, which condition on (k) is correct?

Explanation opens after your attempt
Correct Answer

A. \(k\le9\)

Step 1

Concept

For real roots \(D\ge0\) is required. From \(36-4k\ge0\), we get \(k\le9\).

Step 2

Why this answer is correct

The correct answer is A. \(k\le9\). For real roots \(D\ge0\) is required. From \(36-4k\ge0\), we get \(k\le9\).

Step 3

Exam Tip

वास्तविक मूलों के लिए \(D\ge0\) चाहिए। \(36-4k\ge0\) से \(k\le9\) मिलता है।

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समीकरण \(x^2+4x+k=0\) के वास्तविक मूल होने के लिए (k) के बारे में कौन सी शर्त सही है?

For \(x^2+4x+k=0\) to have real roots, which condition on (k) is correct?

Explanation opens after your attempt
Correct Answer

A. \(k\le4\)

Step 1

Concept

For real roots \(D\ge0\) is required. From \(16-4k\ge0\), we get \(k\le4\).

Step 2

Why this answer is correct

The correct answer is A. \(k\le4\). For real roots \(D\ge0\) is required. From \(16-4k\ge0\), we get \(k\le4\).

Step 3

Exam Tip

वास्तविक मूलों के लिए \(D\ge0\) चाहिए। \(16-4k\ge0\) से \(k\le4\) मिलता है।

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समीकरण \(x^2+2x+k=0\) के वास्तविक मूल होने के लिए (k) के बारे में कौन सी शर्त सही है?

For \(x^2+2x+k=0\) to have real roots, which condition on (k) is correct?

Explanation opens after your attempt
Correct Answer

A. \(k\le1\)

Step 1

Concept

For real roots \(D\ge0\) is required. From \(4-4k\ge0\), we get \(k\le1\).

Step 2

Why this answer is correct

The correct answer is A. \(k\le1\). For real roots \(D\ge0\) is required. From \(4-4k\ge0\), we get \(k\le1\).

Step 3

Exam Tip

वास्तविक मूलों के लिए \(D\ge0\) चाहिए। \(4-4k\ge0\) से \(k\le1\) मिलता है।

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