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Which statement creates a contradiction in the proof that \(\sqrt{2}\) is irrational?

Answer and explanation

Correct answer: \(p\) और \(q\) दोनों सम हैं, जबकि \(\frac{p}{q}\) सरलतम रूप में है।

Assume \(\sqrt{2}=\frac{p}{q}\) with coprime integers \(p,q\). From \(p^2=2q^2\), \(p\) is even, and then \(q\) is also even. This contradicts the fraction being in lowest terms; \(p^2\) being even alone is not a contradiction. Exam tip: state the coprime condition clearly.

Related tags

Number SystemsIrrational NumbersSquare Root 2Proof By ContradictionClass 9 MathematicsProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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