गुणोत्तर श्रेणी \(9,18,36,\ldots\) के पहले (12) पदों का योग क्या है?
What is the sum of the first (12) terms of the geometric progression \(9,18,36,\ldots\)?
Explanation opens after your attempt
A. (36855)
Concept
(S_{12}=9\(2^{12}-1\)=36855). In exams use \(2^{12}=4096\).
Why this answer is correct
The correct answer is A. (36855). (S_{12}=9\(2^{12}-1\)=36855). In exams use \(2^{12}=4096\).
Exam Tip
(S_{12}=9\(2^{12}-1\)=36855) है। परीक्षा में \(2^{12}=4096\) का उपयोग करें।
Login to save your score, XP, coins and progress.
