गुणोत्तर श्रेणी \(12,24,48,\ldots\) के पहले (10) पदों का योग क्या है?

What is the sum of the first (10) terms of the geometric progression \(12,24,48,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (12276)

Step 1

Concept

(S_{10}=12\(2^{10}-1\)=12276). In exams, use \(2^{10}=1024\).

Step 2

Why this answer is correct

The correct answer is A. (12276). (S_{10}=12\(2^{10}-1\)=12276). In exams, use \(2^{10}=1024\).

Step 3

Exam Tip

(S_{10}=12\(2^{10}-1\)=12276) है। परीक्षा में \(2^{10}=1024\) का उपयोग करें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(12,24,48,\ldots\) के पहले (10) पदों का योग क्या है? / What is the sum of the first (10) terms of the geometric progression \(12,24,48,\ldots\)?

Correct Answer: A. (12276). Explanation: (S_{10}=12\(2^{10}-1\)=12276) है। परीक्षा में \(2^{10}=1024\) का उपयोग करें। / (S_{10}=12\(2^{10}-1\)=12276). In exams, use \(2^{10}=1024\).

Which concept should I revise for this Mathematics MCQ?

(S_{10}=12\(2^{10}-1\)=12276). In exams, use \(2^{10}=1024\).

What exam hint can help solve this Mathematics question?

(S_{10}=12\(2^{10}-1\)=12276) है। परीक्षा में \(2^{10}=1024\) का उपयोग करें।